Which of the following lines is perpendicular to the line \( \frac{x-6}{-4}=\frac{y+1}{5}=\frac{z}{3} \) ?
a) \( \vec{r}=(10,-6,-3)+s(1,2,-2), s \in \mathbf{R} \)
b) \( \vec{r}=(6,-1,0)+s(-4,5,3), s \in \mathbf{R} \)
c) \( \frac{x-6}{4}=\frac{y+1}{-5}=\frac{z}{-3} \)
d) none of the above