e. $CH_3-CH_2-CH(Cl)-CH(Br)-CH_3 \rightarrow CH_3-CH_2-C \equiv C-CH_3$
f. \begin{tikzpicture}
\draw (0,0) -- (1,0) -- (1.5,0.866) -- (1,1.732) -- (0,1.732) -- (-0.5,0.866) -- cycle;
\draw (0.5,0.866) -- (1.5,0.866);
\draw (1.5,0.866) -- (2,0);
\draw (2,0) node[right] {$C=CH_2$};
\draw (0.5,0.866) node[left] {$H$};
\end{tikzpicture} $+ CHCl_3 \xrightarrow{NaOH/H_2O}$