Use Euler's method to approximate the solution to the given initial value problem at the points $x = 0.1, 0.2, 0.3, 0.4$, and $0.5$, using steps of size $0.1$ ($h = 0.1$).
$\frac{dy}{dx} = y(2 - y), y(0) = 9$
The approximate solution to $\frac{dy}{dx} = y(2 - y), y(0) = 9$, at the point $x = 0.1$ is $\boxed{}$.
(Round to five decimal places as needed.)
The approximate solution to $\frac{dy}{dx} = y(2 - y), y(0) = 9$, at the point $x = 0.2$ is $\boxed{}$.
(Round to five decimal places as needed.)
The approximate solution to $\frac{dy}{dx} = y(2 - y), y(0) = 9$, at the point $x = 0.3$ is $\boxed{}$.
(Round to five decimal places as needed.)
The approximate solution to $\frac{dy}{dx} = y(2 - y), y(0) = 9$, at the point $x = 0.4$ is $\boxed{}$.
(Round to five decimal places as needed.)
The approximate solution to $\frac{dy}{dx} = y(2 - y), y(0) = 9$, at the point $x = 0.5$ is $\boxed{}$.
(Round to five decimal places as needed.)
