stretching it?
F=Kx
12=K (12(2)-12)
12=K12
K=1
W = \int_{0}^{24} x \, dx = \frac{x^2}{2} \Big|_{0}^{24} = \frac{24^2}{2} - \frac{(0)^2}{2} = 288
A half-square triangular window, as shown on the picture, is on a vertical wall of a tank holding water, with
the top point one foot below the surface level. Find the force of water on the window. The weight-density of
the water is 62.4 lb/ft³.
F = 62.4 \int_{0}^{2} \pi (2y-y^2) \, dy
= 62.4 \int_{0}^{2} (2y^2 - y^3) \, dy
= 62.4 \left( \frac{2y^3}{3} - \frac{y^4}{4} \right) \Big|_{0}^{2}
= 62.4 \left( \frac{2(2)^3}{3} - \frac{(2)^4}{4} \right) = 173.910
