Find the useful power output of an elevator motor that lifts a 3000-kg load a height of 40.0 m in 20.0 s, if it also increases the speed from rest to 4.25 m/s. Note that the total mass of the counterbalanced system is 10,000 kg--so that only 3000 kg is raised in height, but the full 10000 kg is accelerated.
P =
units