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When relative intermolecular forces (IMFs) are stronger, the relative values for the following physical properties are... briling point, by (arcle one) higher or lower b. heat of vaporization, AH_(. ) (circle one) higher or lower c. vapor pressure, P. (circle one) higher or lower

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What is the perspective that views time as a resource that must be divided among our various activities? Question options: time poverty economic time associational time divisional time

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4 pigments (β-carotene, xanthophyll, chlorophyll-a, chlorophyll-b) given in the introduction to the lab handout, rank the pigments from least polar to most polar.

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A second-order reaction has a first half-life of 492 s. What will be the value of the fifth half-life for this reaction? 2460 s 984. s 492. s 30.8 s 7870 s

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????? ?. 50 ???? ??????? ?????????? ??? ???? ????????? ???? ??? 30 ??? ???? ????? ????? ??? ??????? ??????????? ? A contract on construction job spocifies a penally for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 torks, second day, As. 300 for the third day etc, the penality for each succeeding day being Rs. 50 more than for the preceding day. How much money the contractor has to pay as penalty, it he has delayed the work by 30 days. (Ans: Rs. 27,

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25 g of sulfur trioxide contains how many oxygen atoms? Type your answer in the following format: 1) if your answer is 1.23 x $10^{21}$ then type it as 1.23e+21 2) If your answer is 0.0123 or 1.23 x $10^{-2}$ then type it as 1.23e-2

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Texts: Damien and Linda are residents of Australia for tax purposes. They carry on business as a partnership together in Sydney. According to the partnership agreement, Damien and Linda share profits and losses on the basis of: • Damien: 60 percent • Linda: 40 percent. During the year ended 30 June 2022, their trial balance showed the following: Gross sales: $978,000 Interest income: $140 Purchase of trading stock: $414,200 Wages to employees (other than Damien and Linda): $116,000 Salary paid to Damien: $32,000 Drawings by Damien: $14,000 Drawings by Linda: $0 Other tax-deductible expenses: $284,500 Stock on hand at 1 July 2021 was $68,000. Stock on hand at 30 June 2022 was $97,000. For the year ended 30 June 2021, the partnership made a tax loss of $26,000. Required: (a) Calculate the net income of the partnership for the year ended 30 June 2022. (b) Calculate the amount to be included in the assessable income of each partner's personal income tax return for the year ended 30 June 2022.

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Methane, CH$_4$, a colorless gas used as a fuel. Express your answer in atomic mass units to one decimal place. Formula weight = amu

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An industrial process discharges 5,700 m³/min of gaseous products at 480K, 100 kPa. The figure below shows a proposed system for utilizing the combustion products and its steady state conditions. Heat transfer from the outer surface of the steam generator (heat exchanger) and turbine can be ignored, as can the changes in kinetic and potential energies of the streams. There is no pressure drop through the heat exchanger. The combustion product can be modeled as air as an ideal gas. Determine: a) The turbine inlet temperature, T4; b) the power developed by the turbine; and c) the rates of entropy generation in the heat exchanger and turbine, each in kW/K. Combustion products in P1 = 100 kPa T1 = 480 K (AV)1 = 5700 m³/min Combustion products out P2 = 100 kPa T2 = 400 K 4 P4 = 300 kPa Turbine Power out Steam generator 3 Water in P3 = 300 kPa T3 = 40°C ?3 = 120 kg/min 5 Water out P5 = 5 kPa x5 = 97%

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Translate the following C++ program into MAL (MIPS Assembly Langage). Your solution should have all necessary data allocations, input/output instructions etc, and must compile and run correctly in spim. Make sure your loops are efficient (i.e., they should not have unnecessary branches). Given: max is in $s0, num is in $s1, i is in $s2. (These variables should not be allocated in the .data section.) You may use any other $s? or $t? registers as temporaries. #include <iostream> using std::cin; using std::cout; int main() { int max, num, i; max = 100; num = 4; while (max > 42) { for (i=1; i < num; i++) { max = max / i; if ((max > i) || (max < 2)) { cout << max; } } } }

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harold p.