1.Calculate the number of atoms per cubic meter in Aluminum,which is FCC with an atomic radius of 143 pm and an atomic weight of 27.0 /mole.V=rc
Answer for1
2.See Table 1 for a list of metals.For each, the crystal structure,density atomic weight,atomic radius,and valence are given. Determine a.Which metal is most soluble in Gold
Answer for 2a
b.Which metal is most soluble in Chromium?
Answer for2b
3.Calculate the equilibrium number of vacancies per m for Nickel at 700C.The activation energy for vacancy formation at 800C is 1.7 eV/atom. The density and atomic weight for Nickel are provided in Table 1.
Answer for3
4. Calculate the activation energy for vacancy formation in Platinum given that the equilibrium number of vacancies at 800C is 2.03x 1025 vacancies per cubic meter. The density and atomic weight for Platinum are given in Table 1.
Answer for4
Table 1.Properties of Metals
Crystal Atomic Radius, Atomic Weight, Density Metal Structure pm g/mole g/cm Aluminum FCC 143.1 27.0 2.71 Chromium BCC 124.9 52.0 7.19 Copper FCC 127.8 63.5 8.94 Gold FCC 144.2 197.0 10.3 Iron(room temp) BCC 124.1 55.9 7.87 Lead FCC 124.1 207.2 11.4 Molybdenum BCC 136.3 96.0 10.3 Nickel FCC 124.6 58.7 8.9 Platinum FCC 138.7 195.0 21.5 Silver FCC 144.5 107.9 10.5 Tungsten BCC 137.1 183.9 19.3
Valence
+ +2 +2,+1 +1 +2 +2,+4 +2.+3.+4 +5, +6 +2 +1 +1 +2
