EXERCISE
A system consists of two lenses mounted on an optical bench. Lens 1 has focal length 5.80 cm. An object is placed 7.5 cm to the left of this lens. A second lens, Lens 2, with focal length
11.0 cm, is placed to the right of the first lens. A screen is to the right of the second lens. The image on the screen has a magnification of +1.00. What is the distance (in cm) between the
object and the screen?
Hint
First, use the lens equation to find $q_1$, and use this result to calculate $M_1$. Note that $M = M_1M_2 = 1.00$. Use the equation for $M_2$ to find $p_2$ in terms of $f_1$ and $q_2$. Next, use the lens
equation to find $q_2$ in terms of $f_2$ and $p_2$. Substitute your expression for $p_2$ into your equation for $q_2$ and simplify. You should get an expression for $q_2$ in terms of $f_1$ and $f_2$, both
known quantities. Then, find $p_2$. Finally, find the total distance by summing $p_1 = 7.5$ cm, $p_2$, $q_1$, and $q_2$.
Click the hint button again to remove this hint.
29.13
x cm