Use the ratio test to determine whether \sum_{n=18}^{\infty} \frac{3^n}{(6n)^2} converges or diverges.
(a) Find the ratio of successive terms. Write your answer as a fully simplified fraction. For $n \ge 18$,
$\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \frac{\Box}{\Box}$
(b) Evaluate the limit in the previous part. Enter $\infty$ as infinity and $-\infty$ as -infinity. If the limit does not exist, enter DNE
$\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \text{DNE}$
(c) By the ratio test, does the series converge, diverge, or is the test inconclusive? Diverges
