(d) \int_{-\infty}^{-1} \frac{e^x}{x} dx
Since the function $y = \frac{e^x}{x}$ has an infinite discontinuity at $x = 0$, the integral is a Type 1 improper integral.
Since the function $y = \frac{e^x}{x}$ has an infinite discontinuity at $x = -1$, the integral is a Type 1 improper integral.
Since the function $y = \frac{e^x}{x}$ has an infinite discontinuity at $x = 0$, the integral is a Type 2 improper integral.
Since the integral $\int_{-\infty}^{-1} \frac{e^x}{x} dx$ has an infinite interval of integration, it is a Type 1 improper integral.
Since the integral $\int_{-\infty}^{-1} \frac{e^x}{x} dx$ has an infinite interval of integration, it is a Type 2 improper integral.