Numerade

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A logistic regression was built to predict a dependent variable to be either “Yes” or “No.” 75% of the dataset was used to train the model, and the remaining 25% was used to test the resulting model. The prediction performance was evaluated using the test set and presented in the confusion matrix below. Show the steps on how you obtain the result for all questions below for full credit. 1. How many observations were used to train the model? How many observations were used to test the model?

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A small radio transmitter broadcasts in a 46 mile radius. If you drive along a straight line from a city 56 miles south of the transmitter to a second city 60 miles west of the transmitter, for what length of the drive will you pick up a signal from the transmitter? Round your answer to the nearest tenth of a mile.

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Climate Change is a social and an ecological problem and the social and ecological are entangled. Question 10 options: TrueFalse

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8) Prove Property 3 of Theorem 6.13: For square matrices A, B, and C of order n, if A is similar to B and B is similar to C, then A is similar to C. 9) Find all eigenvalues of the matrix $A = \begin{bmatrix} 2 & -1 & 1 \\ -2 & 3 & -2 \\ -1 & 1 & 0 \end{bmatrix}$. Then find the corresponding eigenvectors. More space is provided on the next page! $| \lambda I - A | = \begin{vmatrix} \lambda - 2 & 1 & -1 \\ 2 & \lambda - 3 & 2 \\ 1 & -1 & \lambda - 0 \end{vmatrix}$

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Question 155 of 176 Finish update app.aktiv.com Submit Which of the following symbols represents a beta particle? A $ { }^{0}{ }_{+1} \mathrm{e} $ B $ { }_{-1}^{0} \mathrm{e} $ C $ { }_{2}^{4} \mathrm{He} $ D Y

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which if the following taxpayers will incur a failure to file penalty

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The following results on summations will help us in calculating the sample variance s2. For any constant c, the following apply. n i = 1 c = nc n i = 1 cyi = c n i = 1 yi n i = 1 (xi + yi) = n i = 1 xi + n i = 1 yi Use 1, 2, and 3 to show that s2 = 1 n − 1 n i = 1 (yi − y)2 = 1 n − 1 n i = 1 yi2 − 1 n n i = 1 yi 2 . s2 = 1 n − 1 n i = 1 (yi − y)2 = 1 n − 1 n yi2 − y + y2 i = 1 expand (yi − y)2 = 1 n − 1 n i = 1 yi2 − 2y n i = 1 + ny2 distribute the summation = 1 n − 1 n i = 1 yi2 − 2y y + ny2 simplify the summation = 1 n − 1 n i = 1 yi2 − y2 combine like terms = 1 n − 1 n i = 1 yi2 − 1 n n i = 1 yi 2 replace y with 1 n n i = 1 yi = 1 n − 1 n i = 1 yi2 − n i = 1 yi 2 multiply

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On a production possibilities curve, the optimal or best combination of output for any society: is at a point near the bottom of the curve. is at the precise midpoint of the curve. is at a point near the top of the curve. depends upon the preferences of society.

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1. [10 pt] Show that the electric field of a (perfect) dipole $\mathbf{p}$ can be written in the coordinate-free form as: $\mathbf{E}_{\text{dip}} = \frac{1}{4\pi\epsilon_0 r^3} \left[ 3(\mathbf{p} \cdot \hat{\mathbf{r}})\hat{\mathbf{r}} - \mathbf{p} \right];$ 2. [10 pt] Two dipoles with momenta $\mathbf{p}_1$ and $\mathbf{p}_2$, respectively, are separated by a distance $d$. Calculate the force between the two dipoles.

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2. Given $A \subset \mathbb{R}$, we let $L_A$ be the set of limit points of A and define the closure of A to be $\bar{A} = A \cup L_A$. (a) (*) Show that x is a limit point for A if and only if for any $\epsilon > 0$, there exists $\qquad y \in A \cap (x - \epsilon, x + \epsilon)$ such that $y \neq x$. Now we have two equivalent ways to think of limit points: in terms of sequences or in terms of neighbourhoods. We can translate these into less rigorous terms as follows: (sequences) \"limit points are those points for which I can well approximate by points in A\", (neighbourhoods) \"limit points are those points for which I can always find a point in A arbitrarily close.\"

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javier h.