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jennifer bates

jennifer b.

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Question 1) How is total resistance calculated in a series circuit? a) Add the reciprocal of each resistance b) Add all resistances together c) Multiply all resistances together d) Square each resistance and add them

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a $130,000 home insured for $100,000, based on the 80 percent coinsurance provision, how much would the insurance company pay on a $5,000 claim?

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Other things equal, appreciation of the dollar a increases demand in the United States and may increase aggravated supply by reducing the prices of imported resources increases aggravating demand in the United States and may decrease aggravated supply by reducing the prices of important resources

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Someone can voluntarily waive consent: Question 15 options: a) True b) False

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This question: 5 point(s) possible A study was conducted in which students were asked to estimate the number of calories in a cheeseburger. One group was asked to do this after thinking about a calorie-laden cheesecake. A second group was asked to do this after thinking about an organic fruit salad. The mean number of calories estimated was 782 for the group that thought about the cheesecake and 1002 for the group that thought about the organic fruit salad. Suppose that the study was based on a sample of 20 students in each group, and the standard deviation of the number of calories estimated was 122 for the people who thought about the cheesecake first and 145 for the people who thought about the organic fruit salad first. Complete parts (a) through (e) below. OB. A Type II error is committed if the alternative hypothesis is rejected but the mean estimate is significantly lower for the people who thought about the cheesecake. OC. A Type II error is committed if one concludes that the mean estimate is significantly lower for the people who thought about the cheesecake when it is not significantly lower. OD. A Type II error is committed if the null hypothesis is rejected but the mean estimate is not significantly lower for the people who thought about the cheesecake. d. At the 0.01 level of significance, is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first? Find the test statistic. tSTAT (Round to two decimal places as needed.) State the conclusion of the test. â–¼Ho. There â–¼that the mean number of estimated calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first. e. If you were developing a commercial for a cheeseburger, based on the results of (d), what other foods might you show in the commercial? A. Show both the cheesecake and the organic fruit salad before showing the cheeseburger, so that the cheeseburger will appear healthier. B. Show the cheesecake before showing the cheeseburger, so that the cheeseburger will appear healthier. OC. Show the organic fruit salad before showing the cheeseburger, so that the cheeseburger will appear healthier. OD. Show both the cheesecake and the organic fruit salad after showing the cheeseburger, so that the cheeseburger will appear healthier.

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Q10: We used Fuzzy turbine controller to produce electricity for Home, we need to build fuzzy system of two inputs Temperature and Pressure, and one output Throttle (mechanism by which the flow of a fluid is managed) \begin{itemize} \item Temperature use (0-350) each fuzzy set range is 100 [Cold, Cool, Normal, Worm, Hot] \item Pressure use (0-300) [Weak, Low, Ok, Strong, High] the middle 3 fuzzy sets (Low, Ok, Strong) fuzzy set range is 120, Weak 0-70 and high 190-300. \item Throttle output (-60-60). \end{itemize} Negative long (-60 ... -30) Negative mid (-45 ... -15) Negative small (-30 ... 0) Zero (-15 ... 15) Positive mid (0 ... 30) Positive larg (0 ... 30) If the Temperature input is 215 and Pressure is 150, what is the value of Throttle using center of area. if temperature is cold and pressure is weak then throttle is positive large if temperature is hot and pressure is high then throttle is negative large show works and steps

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Changing the Orbit of a Satellite A space transportation vehicle releases a 504 kg communications satelite while in an orbit 280 km above the surface of the Earth. A rocket engine on the satellite boosts it into a geosynchronous orbit. How much energy does the engine have to provide? SOLUTION Conceptualize Notice that the height of 280 km is much lower than that for a geosynchronous satellite, 35,800 km. Therefore, energy must be expended higher position. Categoriza This example is a substitution problem. Find the initial radius (in m) of the satellite's orbit when it is still in the vehicle's cargo bay. (Round your answer to at least three significant figures.) $r_i = R_E + 280 \text{ km} = 6656$ m Use $E = -\frac{GMm}{2r}$ to find the difference in energies for the satelite-Earth system with the satellite at the initial and final radi. (Use the following as necessary: G, m, $r_i$, and $r_f$.) $\Delta E = E_f - E_i = -\frac{GMm}{2r_f} - \left( -\frac{GMm}{2r_i} \right) = \frac{GMm}{2} \left( \frac{1}{r_i} - \frac{1}{r_f} \right)$ Substitute numerical values, using $r_f = 4.22 \times 10^7$ m. (Calculate $\Delta E$ in J. Round your answer to at least three significant figures.) $\Delta E = 1.27 \times 10^{10}$ J This is the energy equivalent of 96 gal of gasoline. NASA engineers must account for the changing mass of the spacecraft as it ejects burned fuel, something we have not done here. Would you expect the calculation that includes the effect of this changing mass to yield a greater or a lesser amount of energy required from the engine? $\bigcirc$ greater $\bigcirc$ lesser EXERCISE If the engine on the satelite in the Example provides an additional $\Delta E = 2.3 \times 10^{10}$ J of energy to boost the rocket to an even higher orbit, how high above Earth's surface (in m) would the satellite be Hint 40000 m

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ay, March 24th The following information relates to the December 31 adjustments for Water Works, a firm providing waterproofing services for commercial and residential customers. The firm's fiscal year ends December 31 and no adjustments have been made during the year. 1. The firm paid a $2,340 premium for a 1-year insurance policy, coverage to begin November 1. The premium payment was debited to Insurance Expense. 2. Weekly wages for a 5-day work week total $1,225, payable on Fridays. December 31 is Wednesday. 3. Water Works received $3,600 in November for services to be performed during December through February of the following year. When received, this amount was credited to Unearned Service Fees. By December 31, one-fourth of this amount was earned. 4. Water Works receives a 10% commission from the manufacturer on sales of waterproofing agent to Water Work's customers. By December 31, Water Works had sales of $9,000 (during November and December) for which no commissions had been received or recorded. 5. On December 31, the Supplies Expense account has a balance of $16,900 and the Supplies account has a balance of $2,500. A count of supplies on December 31 indicates that $3,500 worth of supplies are still on hand. 6. A customer couldn't pay his bill so on December 1st, Water Works accepted a 6%, 3-month, $40,000 note from John Smith. 7. Water Works rents parking spaces in its lot to firms in the office building next door. On December 1, Water Works received $10,000 as advance payments to cover parking privileges in the lot for December through March of the following year. When received, the $10,000 was credited to Parking Fees Earned. 8. During December, fuel oil costs of $495 were incurred to heat the firm's buildings. Because the monthly bill from the oil company has not yet arrived, no entry has been made for this amount (fuel oil costs are charged to Utilities Expense). 9. On September 1, the company entered into an equipment maintenance contract. Water Works paid $3,000 to cover maintenance service for six months, beginning September 1. The $3,000 payment was debited to Prepaid Maintenance. REQUIRED: Using the information above, prepare December 31st adjusting entries for Water Works. Be sure to label each adjustment using numbers 1 through 9.

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Change the triple integral to spherical coordinates: \(\iiint_Q (x^2 + y^2 + z^2)^{\frac{1}{2}} dV\) Where Q is bounded by the upper hemisphere: \(x^2 + y^2 + z^2 = 100\). \(\int_0^{2\pi} \int_0^{\pi} \int_0^{10} \rho^3 \sin\phi \,d\rho d\phi d\theta\) \(\int_0^{2\pi} \int_0^{\frac{\pi}{2}} \int_0^{10} \rho^3 \sin\phi \,d\rho d\phi d\theta\) \(\int_0^{2\pi} \int_0^{\frac{\pi}{2}} \int_0^{10} \rho^3 \sin\phi \,d\rho d\phi d\theta\) \(\int_0^{2\pi} \int_0^{\pi} \int_0^{10} \rho^2 \sin\phi \,d\rho d\phi d\theta\)

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What is the area of the shaded triangle? 5 cm 12 cm 13 cm 15 cm

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