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jennifer heath

jennifer h.

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3.3 A resistor has a nominal stated value of 10 ฮฉ เต‡ 1%. A voltage is impressed on the resistor, and the power dissipation is to be calculated in two different ways: (1) from ๐‘ƒ เตŒ เฎพ เฐฎ เฏ‹เต— and (2) from ๐‘ƒ เตŒ ๐ธ๐ผ. In (1) only a voltage measurement will be made, while both current and voltage will be measured in (2). Calculate the uncertainty in the power determination in each case when the measured values of ๐ธ and ๐ผ are: ๐ธ เตŒ 100 ๐‘‰ เต‡ 1% แˆบ๐‘“๐‘œ๐‘Ÿ ๐‘๐‘œ๐‘กโ„Ž ๐‘๐‘Ž๐‘ ๐‘’๐‘ แˆป ๐ผ เตŒ 10 ๐ด เต‡ 1%

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Rac+/+ Rac-/- (a) 20 ?m with lamellipodia no lamellipodia 100 percentage of cells (b) 90 80 70 60 50 40 30 20 10 0 Rac+/+ Rac- Rac+/+ Rac- Rac+/+ Rac- Rac+/+ Rac- control Rac gene Rho gene Cdc42 gene transfection transfection transfection transfection Figure 2 Ability of MEF cells to form lamellipodia. (a) Representative fluorescence micrographs of Rac+/+ MEF cells and Rac-/- MEF cells stained with fluorescent phalloidin. White arrows indicate lamellipodia. (b) Graph showing the percentage of cells with and without lamellipodia after transfection with a control 'empty' plasmid, or a recombinant plasmid expressing one of the G proteins Rac, Rho or Cdc42. 300 cells were analysed in each condition. Hide description A Figure 2 consists of two parts, labelled Figures 2a and b. Figure 2a consists of two fluorescence micrographs, each showing one MEF cell. The microfilaments are visible as a network throughout the cell, with brighter staining along the cell membrane. The micrograph on the left-hand side shows a Rac+/+ MEF cell. The cell is elongated and two arrows point to lamellipodia. The micrograph on the right-hand side shows a Rac-/- MEF cell. The cell is star- shaped, and no arrows are shown. The scale bar reads 20 micrometres. Figure 1b shows a bar graph that quantifies the percentage of Rac+/+ and Rac-/- MEF cells that do or do not have lamellipodia. The horizontal axis has four sets of bars. Each set contains two bars: Rac+/+ and Rac-/-. Each bar shows the percentage of MEF cells with lamellipodia in the bottom part in yellow, and the percentage of MEF cells with no lamellipodia on the top part in green. Both parts always add up to 100% as the total height of the bar. The four sets of bars are labelled (from left to right): 'control transfection', 'Rac gene transfection', 'Rho gene transfection'

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Q9 Consider the integral \(\int_0^4 \frac{x}{x^2+1}dx\) (a) Find the approximate value of the integral with the Composite Midpoint rule with \(M = 1,2,3\) (1,2 and 3 subintervals). (b) Find the approximate value of the integral with the Composite Trapezoidal rule with \(M = 1, 2, 4\) (1,2 and 4 subintervals). (c) Find the approximate value of the integral with the Composite Simpson's rule with \(M = 1,2,3\) (2,4 and 6 subintervals). (d) Use the results of part (b)and perform Romberg integration to approximate the given integral.

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Which of the following is NOT a function of the cell membrane? Question 17 options: prevents osmotic lysis detection of environmental signals transport of molecules into and out of the cell production of proteins

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10. Name the monosaccharides that make up sucrose: ANSWER: 11. Are these monosaccharides reducing sugars? Yes or No 12. What is your experimental evidence?_ANSWER:

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Question 2 (20 marks) Fun Pte Ltd is in the business of manufacturing vacuum cleaners. The company is preparing budgets for the new financial year, 2020. The following data has been collected from various departments for the purpose of budgeting for the new financial year, 2020. The company manufactures two product models of vacuum cleaners, that is, So-Clean and So-Easy. The projected sales for the next five quarters are as follows: Quarter 1 2020 Quarter 2 2020 Quarter 3 2020 Quarter 4 2020 Quarter 1 2021 Additional information: So-Clean (units) So-Easy (units) 300 600 1,000 1,500 2,000 2,500 1,500 2,000 500 2,500 1. The estimated unit selling price is $300 for So-Clean model and $500 for So-Easy model. 2. A desired ending inventory is planned at the end of each period to be equivalent to 20% of the following quarter's sales target. The opening inventory balance in 2020 for So-Clean is 300 units and for So-Easy is 200 units. 3. Direct material, So-001 is a common component for both models. For every one unit of So-Clean or So-Easy, 3 units of So-001 is required. Each unit of So-001 costs $25. The desired ending material inventory is planned at the end of each period to be equivalent to 10% of the following quarter's raw materials needed for production. There is no opening material inventory for So-001. Required: (a) Prepare the sales budget for So-Clean and So-Easy (show separately) for each of the FOUR (4) quarters of 2020. (4 marks) (b) Prepare the production budget in units for each of the FOUR(4) quarters of 2020 for the product model So-Clean only. (8 marks) (c) Based on the production budget prepared in (b) for So-Clean only, prepare a purchases budget in units and in dollars for direct materials, So-001 for the first and second quarters of 2020. DIPL/ACC0002/Jan2020/MainEQP (8 marks) Page 4 of 10

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Problem 2.050 ? Your answer is incorrect. Try again. A gas undergoes a process in a piston-cylinder assembly during which the pressure-specific volume relation is $pv^{1.3}$ = constant. The mass of the gas is 0.4 lb and the following data are known: $p_1$ = 160 lbf/in.$^2$, $V_1$ = 1 ft$^3$, and $p_2$ = 300 lbf/in.$^2$. During the process, heat transfer from the gas is 2.1 Btu. Kinetic and potential energy effects are negligible. Determine the change in specific internal energy of the gas, in Btu/lb. $\Delta u$ = -62.19 the tolerance is +/-2% Btu/lb

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3. If $f(z) = x + \frac{x}{(x^2+y^2)} + i(y - \frac{y}{(x^2+y^2)})$ is analytic, show that the real and imaginary parts are harmonic and represent orthogonal families of curves

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CF$_3$-O-CHCl$_2$ CF$_3$H Cmpd I \nu$_P$ 250 $\nu_{max}$ $CCl_4$ CF$_3$CHBrF Cmpd II \nu$_P$ 241.3 $\nu_{max}$ $CCl_4$ CF$_3$-O-CHF CF$_3$ CF$_3$CH-O-CHF Cmpd III \nu$_P$ 664 $\nu_{max}$ $CCl_4$ Cmpd IV \nu$_P$ 1620 $\nu_{max}$ $CCl_4$

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Suppose we would like to solve the integral $\int x^2 e^{8x} dx$ using integration by parts. After selecting $u$ and $dv$ and substituting into the integration by parts formula, the above integral becomes: Select one: a. $\frac{1}{8}x^2e^{8x} - \frac{1}{4}\int xe^{8x} dx$ b. $\frac{1}{8}x^2e^{8x} + \frac{1}{4}\int xe^{8x} dx$ c. $8x^2e^{8x} + \frac{1}{4}\int x^2e^{8x} dx$ d. None of the other options are correct

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