(25) (5 points) The figure below shows two dumbbells, each connected by a rod of negligible mass. Each one rotates about its center of mass, and both axes of rotation are out of the page. For this rotation, the moment of inertia of the top dumbbell is $I$, and for the bottom one, the moment of inertia is $I'$.
$I$
$2m$ $L$ $2m$
$m$ $2L$ $m$
$I'$
Which answer is correct?
(A) $I' = (1/4)I$ (B) $I' = (1/2)I$ (C) $I' = I$ (D) $I' = 2I$
(E) No previous correct