2. Let $y'+P(x)y=Q(x)$ be a first order, linear differential equation.
Then, a general solution for $y$ can be found by multiplying the DE by an integrating factor $\mu(x)$. This will yield the equation:
$\mu(x)y'+\mu(x)P(x)y=\mu(x)Q(x)$
We seek to express the left side of the equation as: $\frac{d}{dx}(\mu(x)y)=\mu(x)y'+\mu(x)P(x)y$
Show that the integrating factor, $\mu(x)$ is given by $\mu(x)=e^{\int P(x)dx}$