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jesse clark

jesse c.

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Question 17 (1 point) Saddam Hussein's government in Iraq had links to al Qaeda and had massive stockpiles of weapons of mass destruction. True False

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23. What is the result of 0 divided by any non-zero number? A. The number itself B. Zero C. One D. Undefined

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The range of electromagnetic spectrum important in heat transfer by radiation is _________ microns. 0.38-0.78 0.5-50 100-1000 18384

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Consider a modified magnetic suspension system described by \begin{align*} \dot{x}_1 &= x_2 \\ \dot{x}_2 &= -\frac{k}{m}x_3 - \frac{L_0ax_1^2}{2m(a+x_1)^2} \\ \dot{x}_3 &= \frac{1}{L(x_1)}\left[-Rx_3 + \frac{L_0ax_2x_3}{(a+x_1)^2} + u\right], \end{align*} where $x_1 = y$, $x_3 = i$(current), $u = v$ (voltage) and $L(x_1) = L_1 + \frac{aL_0}{a+x_1}$. (1) Show that the system is locally feedback linearizable and find the corresponding feedback control law and local diffeomorphism. (2) Use the feedback linearization design technique to design a state feedback control law to stabilize the ball at $y = 0.05m$, assuming that $m = 0.1kg$, $k = 0.001$ N/m/sec, $a = 0.05m$, $L_0 = 0.01H$, $L_1 = 0.02H$ and $R = 1\Omega$. (c) Use the feedback linearization design technique to design a state feedback control law so that the output asymptotically tracks $y_r(t) = 0.05 + 0.012\sin t$. Hint: Define the tracking error $e = y - y_r(t)$ and note that $\dot{e} = x_2 - \dot{y}_r(t)$ and $\ddot{e}$. Apply the feedback linearization method to the $e$-dynamic system to do the problem (c).

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Find the inverse of the given function. \(f(x) = \frac{3 - 4x}{8x - 1}\) Selected Answer: \(f^{-1} = \frac{8x - 1}{3 - 4x}\) I had no idea, just wanted to get something down Response Feedback: [None Given]

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B Vin Vdd (V) VtB (V) VtA (V) Vss (V) A Vss Vout 3 0.3 0.2 0 The output voltage Vout, when Vin = Vdd and Vin = Vss is V and V respectively

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Problem 2 Let X denote the shear strength (psi) of spot welds produced at a certain factory. The PDF of X is: $f(x; \lambda) = \left(\frac{100}{x}\right)\left(\frac{x}{\lambda+1}\right)^{100}$ for $0 \le x \le 1 + \lambda$ $= 0$ otherwise; where $\lambda > -1$. A random sample of 5 welds yields data: $x_1 = 392$ psi, $x_2 = 126$ psi, $x_3 = 201$ psi, $x_4 = 189$ psi, $x_5 = 92$ psi. Use the Method of Moments to obtain an estimator of $\lambda$, and then compute the estimate for this data. [Total: 6 points]

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By applying Buckingham's II theory, show that a rational formula for the loss of pressure \(\Delta p\) when a viscous fluid of density \(\rho\) and viscosity \(\mu\) flows with a mean velocity \(U\) through geometrically similar pipes is given by \(\Delta p = \rho U^2 f_1 \left(\frac{\mu}{\rho U D}\right) \left(\frac{k}{D}\right)\)

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TABLE OF COMBINED LOADING OF SHAFTS Shaft Dia. 1/16 Moment Inch-Pounds 0 0.040 0.079 0.119 0.159 0.198 0.238 Torsion Bending 0.396 0.394 0.388 0.378 0.362 0.342 0.317 0 0.134 0.268 0.402 0.536 0.670 0.804 Torsion 3/32 Bending 1.34 1.33 1.31 1.28 1.23 1.16 1.07 Torsion 0.325 0.590 1.30 1.63 1.95 1/8 3.25 3.24 3.20 3.09 2.98 2.86 2.60 Bending 0.632 1.26 1.89 2.52 3.16 3.79 Torsion 5/32 6.32 6.28 6.18 6.02 5.79 5.47 5.06 Bending Torsion 15.11 2.22 3.33 4.44 5.55 6.66 3/16 11.1 10.9 10.8 10.5 10.3 9.56 8.82 Torsion 0 1.72 3.44 5.16 6.88 8.60 10.3 7/32 17.2 17.1 16.8 16.5 15.8 14.8 13.8 Bending Torsion 70 2.60 5.20 7.80 10.4 13.0 15.6 1/4 26.0 25.3 25.4 24.0 23.0 22.5 20.8 Bending 10 5.06 10.1 15.2 20.2 30 Torsion 5/16 50.5 50.3 49.6 40.2 46.3 43.7 40.4 Bending 0.77 17.5 26.3 35.1 43.8 52.6 0 3/8 87.7 87.4 85.9 83.7 80.4 75.9 70.2 Bending 41.6 62.4 103.2 124.0 Torsion 0 20.6 1/2 207.4 205 200 192 181 168 Bending 208 81.2 121.8 203.0 243.6 Torsion 0 40.6 5/8 404.2 399 387.5 372.3 351.9 325.1 Bending 406.2 70.2 140.4 210.6 280.8 351.0 421.2 Torsion 0 3/4 687.8 669.6 643.3 607.9 561.5 Bending 702 698.4 0.277 0.283 0.317 0.356 0.396 0.236 0.173 0 1.07 1.21 1.34 0.953 0.803 0.572 0 2.20 2.60 3.25 2.31 1.95 1.43 0 4.42 5.05 5.68 6.32 4.51 3.78 2.76 7.77 8.88 66.6 11.1 7.86 6.58 4.73 0 12.0 13.8 15.5 17.2 12.7 10.7 7.53 0 18.2 20.8 2.24 26.0 18.5 15.6 11.3 0 40.4 45.5 50.5 36.1 30.4 2.19 0 61.4 70.2 78.9 62.6 52.6 184 0 145.6 166.4 107.2 208.0 151 127.5 0 284.2 324.8 365.4 406.2 290.2 244.0 177.5 0 491.4 631.8 702 501.3 421.1 305.9 0

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Reservoir (2190) [2] D=350 mm 3L 250 l/s [3] [4] 70 l/s D=600 mm L D=450mm L D=200 mm Cross 40 l/s D=250 mm D=150 mm [1] 45 l/s [7] D=150 mm D=100 mm L D=250 mm 50 l/s D=50 mm Flat Dimension (2050) [5] 45 l/s

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