Question 5
15 points Save Answer
For the circuit in the below figure, C1 = 10 uF, C2 = 47 uF, C3 = 47 uC, R1 = 9.1 Ohm, R2 = 9.1 Ohm, RL = 1.5 Ohm, $|V1| = 35$ V phase 60 degrees, $|V2| = 4$ V phase 170 degrees, and f = 7 kHz. After using Node analysis, the set of second-order equations
written in standard form is:
$(0.1099 + j2.507) V_A + (-j2.0672) V_B = (-13.3314 + j7.6969)$ --> (Equation for Node-A)
$(-j2.0672) V_A + (0.7138 + j2.2619) V_B = (-0.4329 + j0.0763)$ --> (Equation for Node-B)
Solve the equations to determine which of the following is true?
Round up your answer to exactly two decimal points.
Warning: selecting a wrong answer takes marks away.
$C_1$
$C_2$
$C_3$
$V_A$
$V_B$
$V_1$
$R_1$
$R_2$
$R_L$
$V_2$
$|V_B| = 13.54 V
$|V_A| = 18.33 V
None of the answers
$|V_A| = 15.34$ V
Angle of $V_A = -129.75$ degrees
Angle of $V_A = 100.43$ degrees
$|V_B| = 16.28$ V
