Find fundamental solutions, $y_1(t)$, $y_2(t)$, of the differential equation
$y'' + 3y' - 10y = 0$.
$y_1(t) = e^{-2t}$, $y_2(t) = te^{-2t}$
None of the options displayed.
$y_1(t) = e^{-2t}$, $y_2(t) = e^{5t}$
$y_1(t) = e^{-2t}$, $y_2(t) = e^{-5t}$
$y_1(t) = e^{5t}$, $y_2(t) = te^{5t}$
$y_1(t) = e^{2t}$, $y_2(t) = te^{2t}$
$y_1(t) = e^{2t}$, $y_2(t) = e^{-5t}$
$y_1(t) = e^{2t}$, $y_2(t) = e^{5t}$
$y_1(t) = e^{-5t}$, $y_2(t) = te^{-5t}$