Find f.
f'(x) = 12x^3 + \frac{1}{x}, x > 0, f(1) = 10
f(x) = \frac{12x^4}{4} \ln(x) + 9
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SCALCET9 4.9.039.
Find f.
f'(t) = \frac{20}{1 + t^2}, f(1) = 0
f(t) = 20 \arctan(t) - 5\pi
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SCALCET9 4.9.042.
Find f.
f'(x) = \frac{(x + 1)}{\sqrt{x}}, f(1) = 9
f(x) = 2x^{\frac{3}{2}} + 2x^{\frac{1}{2}} + \frac{1}{9}