Assume that you have a sample of n₁ = 8, with the sample mean X₁ = 50, and a sample standard deviation of S₁ = 7, and you have an independent
sample of n2 = 12 from another population with a sample mean of X2 = 34, and the sample standard deviation S2 = 8. Construct a 99% confidence
interval estimate of the population mean difference between µ₁ and µ2. Assume that the two population variances are equal.
$$ \boxed{} \le \mu_1 - \mu_2 \le \boxed{} $$
(Round to two decimal places as needed.)