Long Question 1 - Part c
A kg solid, spherical ball undergoes a pure roll up a curved surface in the vertical plane, as shown in the figure.
The ball's path is described by the equation $y = ax^2$ where \textit{x} and \textit{y} are in units of metres, and $a = \boxed{} m^{-1}$.
At position 2, with coordinates $(x_2, y_2) = (\boxed{}, \boxed{}) m$, the ball comes to rest.
What is the instantaneous angle of inclination ($\theta$, as indicated on the figure) of the curve at position 2?
Number Units +/- 1% [2 Marks]