A baseball is hit when it is 3 ft above the ground. It leaves the bat with initial speed of 178 ft/sec, making an angle of
14° with the horizontal. Assume there is linear drag with a drag coefficient k = 0.39 and an instantaneous gust of wind
that adds a component of - 12.5i (ft/sec). The acceleration due to gravity is g = 32 ft/sec$^2$. Complete parts (a) through
(e).
a. Find a vector form for the path of the baseball using the equations for linear drag, shown below, where r(0) = 0
$\frac{v_0}{k}(1 - e^{-kt}) \cos \alpha$, $y = \frac{v_0}{k}(1 - e^{-kt})(\sin \alpha) + \frac{g}{k^2}(1 - kt - e^{-kt})$
A vector form for the path of the baseball is r(t) = $oxed{}i + oxed{}j$
