Verify that λ, is an eigenvalue of A and that x; is a corresponding eigenvector. -2 2-3 A₁ = 5, x₁ = (1, 2, -1) A2 = -3, x₂ = (-2, 10) 0 A3 = -3, x3 = (3, 0, 1) AX1 = CHW-0 2 = Ax2 = -## A = 2 1 -6 -1 -2 Ax3 -2 2-3 2 1-6 = -1 -2 2-3 -2 BHD. I 2 1-6 1 = -1 -2 0 -1 -2 0 11 5 1 2 = -2 ---- -3 1 = -2 2-3 3 -DE- 2 1-6 0 -1 -2 0 1 -3 0 21x1 = 12×2 13x3
Verify that is an eigenvalue of A and that x is a corresponding eigenvector.
-2
2-3 2 1-6 -1-2 0
1=5,x1=12,-1 2=-3,X2=-2,10
23=-3,x3=3,0,1
AX1=
2
4X2
2
1
22
AX3=
2
1
0
=AX3