If R is the total resistance of three resistors, connected in parallel, with resistances $R_1$, $R_2$, $R_3$, then
$$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}.$$
If the resistances are measured in ohms as $R_1 = 10 \ \Omega$, $R_2 = 50 \ \Omega$, and $R_3 = 16 \ \Omega$, with a possible error of 0.5% in each case, estimate the maximum error in the calculated value of R. (Round your answer to three decimal places.)