A beam of length $l$ and negligible weight is placed horizontally between two smooth inclined surfaces. A block with weight $W$ is supported by the beam.
Consider $l = 6.51m$, $W = 766N$, $\alpha = 25^\circ$, and $\beta = 60^\circ$.
Assuming that the block is small, determine the distance $x$ between center of the block and left end of beam such that the entire setup maintains an equilibrium.
Matlab/Mathematica input:
l = 6.51;
W = 766;
alpha = 25;
beta = 60;
$x = \text{number (rtol=0.01, atol=1e-05)}$
m
