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josefa blackwell

josefa b.

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Find the first derivative with respect to x of this function: f(x)=ln⁡(1x)

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weighs 50 pounds and each bag of sugar weighs 20 pounds. The bakery wants to buy at least three times as many bags of sugar as bags of flour. If \( f \) represents the number of bags of flour and \( s \) represents the number of bags of sugar, where \( f \) and \( s \) are nonnegative integers, which of the following systems of inequalities represents this situation? A) \[ \begin{array}{l} 50 f+60 s \leq 750 \\ f \leq 3 s \end{array} \] B) \[ 50 f+20 s \leq 750 \] \[ f \leq 3 s \] C) \[ 50 f+20 s \leq 750 \] \[ 3 f \leq s \] D) \[ \begin{array}{l} 150 f+20 s \leq 750 \\ 3 f \leq s \end{array} \]

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Differentiate the function.\ f(x) = (3x^4 - 2)^{22}

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Short Answer Answer any 2 of the following 3 questions. your choice. Each question is worth 5 points, and all parts are equally weighted unless indicated. If you answer all 3 questions I'll count your best 2 scores. 1. Figure 2 shows the situation for a country that has imposed a tariff on an imported good: 3.5/5 P A Domestic supply DWL B Revenue World price + tariff World price Domestic demand QSI 52 QD2 QDI Q Figure 2 a. On the figure, label the free trade (domestic) quantity demanded and supplied as QD1 and QS1, respectively. b. Label the post-tariff quantities demanded and supplied as QD2 and QS2, respectively. c. Shade in the area(s) representing the deadweight loss from the tariff d. Label the area(s) representing the increase in producer surplus as E (use the same letter if there's more than one area). e. If the total reduction in consumer surplus is $150 million, the deadweight loss is $30 million, and the increase in producer surplus is $50 million, how much revenue does the tariff generate for the government? 1/2 bh 150+50-30= 120 $ 120 milion

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Which statement is true for gases: a. gases are less easy to compress than liquids b. gases have lower density than liquids c. gases have higher viscosity than liquids d. gases are not affected by temperature Which statement is true for viscosity: a. Viscosity is Not a fluid property b. fluid viscosity is highly affected by temperature c. viscosity of liquids is less than viscosity of gases d. fluid viscosity cannot be measured

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Use mathematical induction to prove that for all $n \in \mathbb{N}_+$, we have the following: $(M^{-1}XM)^n = M^{-1}X^nM$. (Here $M$ is any invertible matrix and $X$ is any square matrix.) $\begin{pmatrix} \lambda & 1\\ 0 & \lambda \end{pmatrix}^n = \begin{pmatrix} \lambda^n & n\lambda^{n-1}\\ 0 & \lambda^n \end{pmatrix}$.

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Which statement about the diffusion of O2 and CO2 across the alveolar membrane is true? the diffusion rate for O2 is higher than the diffusion rate for CO2 the concentration gradient for O2 is higher than the concentration gradient for CO2 the permeability for O2 is higher than the permeability for CO2

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5. Vibration of a string of length $\pi$ that is subject to tension and damping is governed by $\frac{\partial^2 u}{\partial t^2} + 2\frac{\partial u}{\partial t} = \frac{\partial^2 u}{\partial x^2}$, $0 < x < \pi$, $t > 0$, (5) where $u(x, t)$ is the transverse displacement of the string at a position $x$ along the string and time $t$. The ends of the string are fixed, hence the boundary conditions are $u(0, t) = u(\pi, t) = 0$, $t > 0$. (6) Suppose that the initial displacement and velocity are $u(x, 0) = 2\sin x$, $u_t(x, 0) = 0$, $0 < x < \pi$, (7) respectively. Use separation of variables to solve equation (5) subject to boundary conditions (6) and initial conditions (7). If applicable, you may use the result that the eigenvalues of the boundary-value problem $X'' - \lambda X = 0$, $X(0) = 0$, $X(\pi) = 0$, are $\lambda_n = -n^2$ for $n = 1, 2, \dots$, with corresponding eigenfunctions $X_n(x) = \sin nx$. [TOTAL 14 marks]

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b. What is the volume of the cube in cubic centimeters? (3 points) Solution and answer: 4 cm V = 2.5 cm 6.5 cm

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18. If $x^2 - xy + y^2 = 3$ find $y''$ (second derivative) \begin{align*} \text{A. } \frac{18}{(x-2y)^2} \\ \text{B. } \frac{12}{(x-2y)^3} \\ \text{C. } \frac{12}{(x-2y)^2} \\ \text{D. } \frac{18}{(x-2y)^3} \end{align*}

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