?Part A
An electric dipole is made of two charges of equal magnitudes and opposite signs. The positive charge, q=7.0 µC, is located at the point (x,y,z)=(3.0 cm,0 cm, 0 cm)
, while the negative charge is located at the point (x,y,z)=(-3.0 cm, 0 cm, 0 cm). How much work will be done by an electric field \(\vec{E}=(6.0\times10^6\text{ N/C})\hat{j}\) to rotate the
dipoles by 60$^\circ$?
Hint: \(\hat{j}\) is the unit vector along the y axis (same as \(\hat{y}\))
? 2.2 J
? 0.3 J
? 5.2 J
? 0 J
? 21.8 J
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