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joseph hernandez

joseph h.

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2. Consider the \( f(x) \) and \( g(x) \) defined as the piecewise function and the graph below \[ f(x)=\left\{\begin{array}{ll} 3 x+2 & x<1 \\ 2 x^{2}-3 x+6, & x \geq 1 \end{array}\right. \] a) Find \( \lim _{x \rightarrow 1} f(x) \) if it exists. Justify your answer (5 marks) b) \( \lim _{x \rightarrow-1} f(g(x)) \) or state that it does not exist (5 marks)

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For the following homogeneous system, write the solution set to the system in a parametricform: + + = 02 + = 03 + + = 0.

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Write the logarithmic equation in exponential form. For example, the exponential form of \( \log _{5} 25=2 \) is \( 5^{2}= \) \[ \log _{2} 4=2 \] \( \square \) Additional Materials

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csc(u - v)

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Your output should look something like what's printed below on the left side of the page. Name - Bob Smith Age - 21 Name - Jimmy John Age - 18 Name - Amy Goldberg Age - 20 Name - Dan Marlo Age - 17 Name - Sally Sorrow Age - 16 --- AFTER SORTING --- Name - Sally Sorrow Age - 16 Name - Dan Marlo Age - 17 Name - Jimmy John Age - 18 Name - Amy Goldberg Age - 20 Name - Bob Smith Age - 21 Here's a little function to sort an array of integers. You can use this as an example of how to sort a list of ages, but the ages you need to sort are in a structure, not an array. void sort(int n, int a[]) { int i, j, temp; for(i=0; i<n-1; i++) { for(j=i+1; j<n; j++) { if(a[i] > a[j]) { temp = a[i]; a[i] = a[j]; a[j] = temp; } } } }

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Guess the value of the limit (if it exists) by evaluating the function at the given numbers. (It is suggested that you report answers accurate to at least six decimal places.) $e^{3.7x} - e^{1.6x}$ Let $f(x) = \frac{e^{3.7x} - e^{1.6x}}{x}$. We want to find the limit $\lim_{x \to 0} \frac{e^{3.7x} - e^{1.6x}}{x}$. Start by calculating the values of the function for the inputs listed in this table. $x$ $f(x)$ 0.2 0.1 0.05 0.01 0.001 0.0001 0.00001 Based on the values in this table, it appears $\lim_{x \to 0} \frac{e^{3.7x} - e^{1.6x}}{x} = $

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1. Determine $V_o$ and the current through the 2 $k\Omega$ resistor. ($V_o = -1$ V, $I = 2$ mA)

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%Homework 2, Problem 2, 4.25(b) clc; clear all; close all; \Sigma_{}xmEt W; %symbolic variables t:time, w:frequency x(t)=1+piecewise(t<-1,_{-},-1<=t<=0,_{-},0<t<=1,_{-},1<t<=2,_{-},2<t<=3, 1,t>3,_{-}); %<-complete blanks in red first before running code. %PART b X= int(x,-1,3); disp('4.25 Part b, X=') Show completed MATLAB code above + copy/paste result from the Command window: Solve 4.25 (c) two different ways: i. by hand -Using this equation: $x(t) = \frac{1}{2\pi} \int_{-\infty}^{\infty} X(j\omega)e^{j\omega t} d\omega$ -Find x(0) from graph and plug it in answer: $x(0) = \frac{1}{2\pi} \int_{-\infty}^{\infty} X(j\omega)d\omega$ or $\int_{-\infty}^{\infty} X(j\omega)d\omega = 2\pi x(0)$ -Type answer below: Answer: _______ ?

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8 (3 Points) The transfer function of a system is $F(s) = \frac{64}{s^2 + 12s + 64}$ then the un-damped natural frequency, damping ratio, and peak time respectively are: 8, 0.75, 0.59 9

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The diagram below shows a floor plan for room P and room Q rented by Syarikat ADZ. The plan is drawn using a scale of 1:300. 8 cm 5.4 cm 6 cm State the actual length, in m, of the floor of the room P.

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