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joshua landa

joshua l.

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E7.2 Use the differential equation approach to find $v_o(t)$ for $t > 0$ in Fig. E7.2. Plot the response. ANSWER: $v_o(t) = 12 - 5e^{-t/0.015}$ V. Figure E7.2 9 V 6 k$\Omega$ 6 k$\Omega$ $t = 0$ $v_o(t)$ 2.5 $\mu$F 6 k$\Omega$ 2 mA

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41. If $f(x) = x^2 - 5x^2$ then what is $f(x)$ when $x = -1$ ? -19 -18 6 42

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Mark all true statements. Group of answer choices It is possible for a positive integer to have two prime factorizations such that the prime factor 3 appears in one of them but not the other. A prime number is a positive integer that is only divisible by 1 and itself. The sum of two primes is prime. If p and q are distinct primes, then they are also relatively prime to each other. To test whether 101 is prime, you only need to divide it by 2,3,5 and 7. If it is not divisible by any of those numbers, then it is prime. If there are only finitely many primes, then 1=2. The number n can have at most the floor of base-2 log of n many prime factors, if prime factors are counted with repetition (i.e. 2*3*3*5 has 4 prime factors.) If p is prime and n is a positive integer, then the number pⁿ has exactly n positive divisors. The sequence of prime numbers follows no exact pattern. If p and q are primes, then pq+1 is also prime. The number of prime numbers between 1 and 100 is greater than the number of prime numbers between 1000 and 1100. If the positive integers a and b are relatively prime, then so are a+1 and b+1. If p is prime, then p+2 may or may not be prime, i.e. there exist primes p such that p+2 is prime, and there exist primes p such that p+2 is not prime. There is a largest prime, and it is about the size of Graham's number.

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In a time-of-flight (TOF) mass analyzer _____. ions are distinguished on the basis of their mass-to-pI ratios larger particles travel faster than smaller particles of the same charge a laser pulse converts some of the analyte into the gas phase highly charged particles travel faster than lower charged particles of the same size

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How many grams of F are in 365 g $CaF_2$? mass:

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Vaughn Corporation issued the following statement of cash flows for 2022. VAUGHN CORPORATION Statement of Cash Flows\textendashIndirect Method For the Year Ended December 31, 2022 Cash flows from operating activities Net income $55,300 Adjustments to reconcile net income to net cash provided by operating activities: Depreciation expense $10,000 Decrease in accounts receivable 8,500 Increase in inventory (4,800) Decrease in accounts payable (2,300) Loss on disposal of plant assets 3,100 14,500 Net cash provided by operating activities 69,800 Cash flows from investing activities Sale of investments 3,300 Purchase of equipment (26,400)

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Question #15 What is the pH of a 0.58 M carbonic acid ($H_2CO_3$) solution given $K_{a1} = 4.4 \times 10^{-7}$ and $K_{a2} = 4.7 \times 10^{-11}$ ? pH =

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Find the equation of the line through the point (-4,3) perpendicular to the line 2x 5y =83

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In evaluating current versions of traditional literature, it is appropriate for which of the following features to be rich rather than simple? A) plot and characters B plot and language C characters and setting D language and illustrations E setting and characters

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10. What does the following function return? node* list_search(node *head_ptr, double x) { node *ptr; for (ptr = head_ptr; ptr != NULL; ptr = ptr->get_next()) if (x == ptr->get_value()) return ptr; return NULL; } A. the value of x B. the position in the linked list of the node containing the value of x C. TRUE or FALSE D. a pointer to the node containing the value of x or the NULL pointer E. a pointer to the node containing the first value greater than x or the NULL pointer 11. The two lines of code below will insert a new node into a linked list at which location? node *ptr = new node(x, head_ptr); head_ptr = ptr; A. after the node pointed to by head_ptr->get_next(); B. at the beginning of the linked list C. after the node pointed to by head_ptr D. at the end of the linked list 12. What will be the value of x after the following code segment executes? head ptr 10 20 70 90 NULL int x; node *ptr1, *ptr2; ptr1 = head_ptr; ptr1 = ptr1->get_next(); ptr2 = ptr1->get_next(); x = ptr2->get_value() - head_ptr->get_value() - ptr1->get_value(); 13. What will be the value of x after the following code segment executes? int x = 50, y = 20; int *xptr = &x; int *yptr = &y; *yptr = 2 * y; *xptr = 4*(*yptr) - *xptr;

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