Entered
(y^4)-16*(y^3)+98*
(y^2)-272*(y^1)+289*y
= 0
y = [e^(4*x)]*
[(c1+c2*x)*cos(x)+
(c3+c4*x)*sin(x)]
At least one of the answers above is NOT correct.
Suppose that a fourth order differential equation has a solution y = 2e^{4x}x sin(x).
Find such a differential equation, assuming it is homogeneous and has constant
coefficients.
y^(4)-16y^(3)+98y^(2)-272y^(1)+289y=0
Find the general solution to this differential equation. In your answer, use c1, c2, c3
and c4 to denote arbitrary constants and x the independent variable. Enter c1 as
"c1", c2 as "c2", etc. Enter the solution as an equation y =?.
y=e^(4x)((c1+c2x)cosx+(c3+c4x)sinx)
Answer Preview
y^4 - 16y^3 + 98y^2 - 272y + 289y = 0
y = e^{4x}((c1 + c2x) cos(x) + (c3 + c4x) sin(x))
Result
incorrect
correct
help (equations)
help (equations)