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juana perez

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Use the given data to find the minimum sample size required to estimate a population proportion or percentage.
Margin of error: three percentage points; confidence level: $95 \%$; from a prior study, $\hat{p}$ is estimated by the decimal equivalent of 87\%.

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: three percentage points; confidence level: $95 \%$; from a prior study, $\hat{p}$ is estimated by the decimal equivalent of 87\%.

Elementary Statistics

Estimates and Sample Sizes

Estimating a Population Proportion

Questions asked

INSTANT ANSWER

We alreade know that \( v|t|=d / \) dit \( x / 0] \) [wheretry \( a(t]=\mathrm{d} 2 / \mathrm{di} 2 \mathrm{z} \mid \mathrm{L}] \) We will new use that to \( p \) redict from ptrpical prindiples how long the period of eselvion of a massi attaded to a spring gahes. frem Nowern's setand law we know that a \( =\mathrm{Ff} / \mathrm{m} \) From hocher's law we krow that forodule \( -k \) * bly Which is the first reselt of this lab, and where \( k=1 / \) slope of the graph of dy ns ESedec that you already made. The unici of kmest be Nim. When we hang a mais from the iprizg and wit for it to be still, after being ast1, if we stred er cempreis the That force will be applied to the mais hanying from the sprizg. That mais wil accelerate acterding to If we now decide that the initial rest positien of the mask, \( x 1 \) is \( =0 \) so that \( 2 x-x 2-x 1=x(0]-0=x(0] \) than since a|t \( =d 2 / \) d.2 \( 2(0) \) we hawe that a condition that afy furction that attampts to descriae the motion of a mais attached to a yerifes and that mover under the force of than spring must mest. If we find a function than satifies that condition, and it ia the mest generilly applicable form of then function, then that fuly deser bes the motion of that masi attadhed to a sprife- This cendition is faffled firy making the double derivative an it to sev if it is fufiled] Whare \( A \) is the ampitude of the movement (ohe mudmum ditarce that the mais reacher with respoct to whare it was still, hatgires by itwelf from the sprindl T is the period of the meticn fohe time it taloes for the mans to go and return and oomplate ene cycle of its repetitive metion _ when \( t=0 \) and when \( t=T \) a 1 gigives the same vilue and the mass is movire is the same direction at the saime speed \( \rightarrow \) has complated coe cycle of its movememt \( \mathrm{m} \) is the mas of the mash hanging from the sprizg. in ly \( k \) is tha sering constant th is how long it has been since the mas wir released \( \phi \) allows the furction to adfust to whare the masi was at time \( t=0 \), without affecting \( A \) of \( T \) of the musimant. of the mins.. in fact it can even corwert the conifa function bo tha sine fanction from all this we leamed that Select are or mare than afk: a. When \( \mathrm{t}=0 \) the position of the mais is \( \mathrm{x}=\mathrm{A} \) jdewtwards \( \mathrm{x} \) is \( p \) es tive) we get that \( d 2 / d 12 n|t|=-k / m^{*} x|u| \) only if \( \mathrm{T}=2^{*} \mathrm{n}[\mathrm{m} / \mathrm{k}] 1 / 2 \) d. whan \( t=0 \) the position of the mass i \( x=-A \) (bo the right \( x \) is positive]

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Supratim Pal verified

Numerade educator

An 18 kg child was going 2 m/s on skates when he collided with a 73 kg adult who was going -1.8 m/s. Both remain loose after the collision, which is elastic. How fast is the boy moving immediately after the crash? Please check: https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Mechanics_and_Relativity_(Idema)/04%3A_Momentum/4.07%3A_Totally_Elastic_Collisions

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Supratim Pal verified

Numerade educator

A 16 kg child was going 2 m/s on skates when he collides with an 81 kg adult who was going -0.7 m/s. Both hold on and do not come loose during and after the crash. How fast is the child/adult moving immediately after the crash? vf to m/s Suggestions Here the visible energy of the movement is not conserved (part of it is converted into thermal energy) but -as always- the momentum is conserved for this system of objects. before the crash Ptotal i = m1v1i +m2v2i After the collision the two objects merge into one and move together as an object of mass m1 + m2, and therefore Ptotal f = (m1 + m2)vf conservation of momentum Ptotal i = Ptotal f whereby m1v1i +m2v2i = (m1 + m2)vf RESPONSE:

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ANSWERED

Jacob Fry verified

Numerade educator

A car of mass 1271 kg is traveling at 53 m/s. A force of -508 N is applied to it for 4.4 s. Obtain its final linear momentum. Suggestions: linear momentum is the same as impetus or momentum Calculate the initial momentum Calculate the impulse given to it Calculate the final momentum based on the previous two. Remember that momentum is the change in momentum. RESPONSE:

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Jacob Fry verified

Numerade educator

A force of 453 N is applied to a car for 5 s. Calculate the momentum this gives the cart.

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ANSWERED

Jacob Fry verified

Numerade educator

A car has a mass of 1186 kg and is traveling at -36 m/s. Calculate its linear momentum.

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Krystal K verified

Numerade educator

An airplane of mass 1000 kg flies at 934 mi/h. It descends from a height of 1648 m to a height of 503 m. Assuming there is no drag from the air, what would be the new speed of the plane? (in mi/h) EYE: g = 9.81 m/s2 1 mi = 1609 m Watch out for units! Suggestions: change to m/s calculate the kinetic energy at the beginning calculate the potential energy at the beginning Calculate the total energy at the beginning Ek + Ep Calculate the potential energy at the end. The total energy at the end is the same (if any of the Ep dropped, it was added to the Ek and the total remains the same) Knowing that the final total energy is the same as at the beginning, subtract from the total the Final ep to get the final Ek from the final Ek, clear for the vf and get the vf Change back to mi/h RESPONSE:

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Jacob Fry verified

Numerade educator

Calculate the potential energy of an airplane of mass 8369 kg at an altitude of 12759 m. IMPORTANT: g=9.81m/s2

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ANSWERED

Jacob Fry verified

Numerade educator

A 1.5 kg box is dragged 4 cm across a surface. The coefficient of kinetic friction is ?k = 6.7. Calculate the work done by the friction force (in J) NOTE: The appropriate sign is essential. Be careful with the units. g = 9.81 m/s2 Suggestions: Calculate the normal force for this situation. Calculate the force of friction Determine the relationship between the directions of the friction force and the displacement calculate the work RESPONSE:

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ANSWERED

Jacob Fry verified

Numerade educator

A boy is traveling at +1.9 m/s on his bicycle (total mass 32 kg). His father applies a force of +2 N to him while the boy moves +1.9 m. Obtain the final kinetic energy of the boy on the bicycle.

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