In $\triangle ABC$, the measure of $\angle A$ is $60^\circ$, the length of the side opposite $\angle A$ is $\sqrt{3}$ inches, and the length of the side opposite $\angle B$ is $\sqrt{2}$ inches. What is the measure of $\angle B$?
(Note: For a triangle with sides of lengths a, b, and c that are opposite angles $\angle A$, $\angle B$, and $\angle C$, respectively,
$\frac{\sin \angle A}{a} = \frac{\sin \angle B}{b} = \frac{\sin \angle C}{c}$)
A. $30^\circ$
B. $40^\circ$
C. $45^\circ$
D. $60^\circ$
E. $90^\circ$
