A torus (the surface of a donut) can be parameterized by
r(?, ?) = (bcos?+a cos ? cos ?, b sin ?+a cos ? sin ?, a sin ?), 0 ? ? ? 2?, 0 ? ? ? 2?
where ? and ? are the angles shown below, b is the distance from the center of
the \"donut hole\" to the center of the \"donut body\" and a is the radius of the
\"donut body\". (Note that 0 < a < b.) Use this parametrization to calculate
the surface area of a torus. It'll look scary at first, but look for opportunities
to factor out expressions that are common to all the components and to
simplify by using $sin^2x + cos^2x = 1$.