Book Problem 4
If $f^{(n)}(5) = \frac{(-1)^n n!}{2^n(n+4)}$ for $n = 0, 1, 2, \dots$, then the Taylor series for $f$ centered at 5 is
$f(x) = \sum_{n=0}^{\infty} \text{\boxed{\phantom{a}}} (x - 5)^n$.
f(x) = $\text{\boxed{\phantom{a}}}$ + $\text{\boxed{\phantom{a}}}$$(x - 5)$ + $\text{\boxed{\phantom{a}}}$$(x - 5)^2$ + $\text{\boxed{\phantom{a}}}$$(x - 5)^3 + \dots$
