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kimberly seco

kimberly s.

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The area of a triangle with vertices (π‘₯1, 𝑦1),(π‘₯2, 𝑦2), (π‘₯3, 𝑦3) can be found by the following equation 𝐴 = 1 2 |π‘₯1(𝑦2 βˆ’ 𝑦3) βˆ’ π‘₯2(𝑦1 βˆ’ 𝑦3) + π‘₯3(𝑦1 βˆ’ 𝑦2)| Write a function that takes a vector of x points and a vector of y points and calculates (and outputs) the area of the resulting triangle. B. Any convex polygon can be broken up into a series of interior triangles. Write a second function that takes a vector of x locations and a vector of y locations for a polygon. The code should systematically send groups of three points (as vectors of x and y data) to the function you wrote in (a) and calculate the area of the polygon based on the output from (a). An n-sided polygon has n-2 triangles on the inside. Start with an easy test case like a square. C. A fair, six-sided die has a 1/6 chance of landing on any given side. However, let’s assume that we have a weighted die that causes sides 1 and 5 to turn up twice as often as any other side. i. Simulate throwing a fair die one time. Have your code determine which side (1-6) was rolled. The rand command will help here. ii. Weight the die so that sides 1 and 5 will turn up twice as often as any other side. Rewrite the code form (i) to take this into account. iii. Simulate throwing a die over and over a lot of times for the fair and weighted cases. Count up how many times each side was rolled and calculate the probability for each. You should see that side 1 and side 5 come up twice as often.

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A bob vibrates up and down on a vertical spring. If the period of the motion is two seconds, the frequency is

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Humans’ motivation to share experiences and goals allow formuch less evidence for such motivation among chimpanzees and other primates

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____________ is the tiny pit in the retina that contains all ___________. Name the eye neuron that functions in dim light and is the most numerous.

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Find the median and mean for each data set. Shoe Size 9,8,8.5,6.5,10,8,10 7,10,7.5,7,7,7,8 6.5, A

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Find the number of SchrΓΆder path from (0, 0) to (5, 5) whose first step is not diagonal.

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Given that $\int_5^8 f(x)dx = \frac{27}{7}$, what is $\int_8^5 f(s)ds?$

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1*. Two six-year old twins, Lisa (L) and Malcolm (M), have the following initial endowments of Cookies and Apples: $\bar{C}_L = 5, \bar{A}_L = 5, \bar{C}_M = 5, \bar{A}_M = 5$ Let $C_L, A_L$ denote Lisa's consumption and $C_M, A_M$ denote Malcolm's consumption of Cookies and Apples. Lisa and Malcolm have the following utility functions: $U_L(C, A) = C \cdot A$ $U_M(C, A) = C + 2A$ a) Calculate a competitive equilibrium when Lisa and Malcolm decide to trade with each other. b) Draw an Edgeworth diagram with Lisa in the lower-left corner and Malcolm in the upper-right corner, where consumption of Cookies is measured on the horizontal axis and consumption of Apples is measured on the vertical axis. Identify the initial endowments and draw the indifference curves of Lisa and Malcolm consistent with these endowments. c) Show graphically the Pareto dominating space given the initial endowments and show that the competitive equilibrium is Pareto-efficient. d) Explain the contract curve concept, and depict it graphically for Lisa and Malcolm. Explore how different positions on the contract curve can be achieved by means of redistribution of endowments. (Choose a different endowment point and calculate a new equilibrium. Try to find the equation for the contract curve) e) What are the relations among the different parts of this question and the First- and Second Welfare Theorems?

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Page 493 in Global Marketing and the Digital Revolution 15-9 Further economic liberalization in Africa depends, in part, on government leaders overcoming suspicions that foreign companies want to exploit Africa. How quickly is this likely to happen? Explain?

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For the following Differential Equations, determine the General Solution / Particular Solutions. WRITE YOUR ANSWERS NEATLY AND LEGIBLY. UPLOAD IMAGES OF YOUR HANDWRITTEN SOLUTIONS. BOX ONLY THE FINAL ANSWER. $\frac{dr}{d\theta} = \frac{r^2}{\theta}; r(1) = 2$ $(1 - e^x)dy + y^{-2}e^x \text{csch } y dx = 0$ $\frac{dy}{dx} = (y^3 - 4y^2 - 5y)(2x - 3)^3$ $y' = \frac{3x^2 - e^x}{2y - 5}; y(0) = 1$

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