Use a graph to estimate the coordinates of the lowest point and the leftmost point on the curve \\
$x = t^4 - 3t$, $y = t + 6t^4$. Then find the exact coordinates.\\
$(x, y) = (\frac{145}{48}, (\frac{1}{3})^{\frac{1}{3}}, -\frac{3}{8}(\frac{1}{3})^{\frac{1}{3}}) $ (lowest point)\\
$(x, y) = (-4.5(\frac{3}{2})^{\frac{1}{3}}, 10(\frac{3}{2})^{\frac{1}{3}})$ (leftmost point)