For H$_2$(g) + Br$_2$(g) $\rightleftharpoons$ 2HBr(g), K = 7.2 × 10$^{-4}$ at 1362 K and $\Delta H^*$ is positive. A vessel is charged with 50.0 Pa HBr, 1430 Pa H$_2$, and 3360 Pa Br$_2$ at 1362 K.
Will the reaction proceed to the left or right to reach equilibrium?
right
left
Calculate the pressure (in pascals) of each species at equilibrium.
$P_{H_2}$ = 1429.5