Solve for the angle $\theta$, where $0 \le \theta \le 2\pi$: \\
$7\sqrt{3}\cos^2(\frac{\theta}{2}) = \frac{14\sqrt{3} + 7\sqrt{9}}{4}$ \\
$\circ \quad \theta = \frac{11\pi}{6}$ \\
$\circ \quad \theta = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}$ \\
$\circ \quad \theta = \frac{\pi}{6}, \frac{11\pi}{6}$ \\
$\circ \quad \theta = \frac{\pi}{6}$ \\
$\circ \quad \theta = \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi$
