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laura mancebo

laura m.

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A parallel-plate capacitor with capacitance $$C_0$$ stores charge of magnitude $$Q_0$$ on plates of area $$A_0$$ separated by distance $$d_0$$. The potential difference across the plates is $$\Delta V_0$$. (a) If the capacitor is attached to a battery and the charge is doubled to $$2Q_0$$, what are the ratios $$\frac{C_{new}}{C_0}$$ and $$\frac{\Delta V_{new}}{\Delta V_0}$$? (b) $$\frac{\Delta V_{new}}{\Delta V_0} =$$ (c) $$\frac{C_{new}}{C_0} =$$ (d) A second capacitor is identical to the first capacitor except the plate area is doubled to $$2A_0$$. If given a charge of $$Q_0$$, what are the ratios $$\frac{C_{new}}{C_0}$$ and $$\frac{\Delta V_{new}}{\Delta V_0}$$? (e) $$\frac{C_{new}}{C_0} =$$ (f) $$\frac{\Delta V_{new}}{\Delta V_0} =$$ (g) A third capacitor is identical to the first capacitor, except the distance between the plates is doubled to $$2d_0$$. If the third capacitor is then given a charge of $$Q_0$$, what are the ratios $$\frac{C_{new}}{C_0}$$ and $$\frac{\Delta V_{new}}{\Delta V_0}$$? (h) $$\frac{C_{new}}{C_0} =$$ (i) $$\frac{\Delta V_{new}}{\Delta V_0} =$$

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Question B3: Two immiscible (i.e. do not mix) liquids flow in a very long, horizontal, two-dimensional channel (i.e. negligible spanwise gradients). The channel has a constant height $2h = 0.02m$. The bottom fluid has a density of $1200 \text{ kg/m}^3$ and a dynamic viscosity of $0.01 \text{ Pa-s}$. The top fluid has a density of $1000 \text{ kg/m}^3$ and a dynamic viscosity of $0.001 \text{ Pa-s}$. The flow is driven by a constant pressure gradient of $\text{dP/dx} = -1 \text{ Pa/m}$. The liquids wet the solid walls, which are non-porous. The flow is steady. a) State the boundary conditions. b) Determine the velocity profile. c) What is the shear stress at the walls and the liquid interface? d) What is the flow speed at the interface? e) Sketch the velocity profile. Determine where the maximum velocity occurs. Hint: It is easier if you set the coordinate axis origin at the centre of the channel as shown. $h = 0.01m$ $y, v$ $x, u$ $h = 0.01m$ $\text{dP/dx} = -1 \text{ kPa/m}$ $\rho_1 = 1000 \text{ kg/m}^3$ $\mu_1 = 0.001 \text{ Pa-s}$ $\rho_2 = 1200 \text{ kg/m}^3$ $\mu_2 = 0.01 \text{ Pa-s}$ Figure B3: Sketch of the flow in a two-dimensional channel driven by $\text{dP/dx} = -1 \text{ kPa/m}$.

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A certain liquid has a vapor pressure of 485 mmHg at 17.1 °C and 631 mmHg at 49.1 °C. Calculate the value of the enthalpy of vaporization, $\Delta H_{vap}$, in kJ/mol for this liquid. Express your answer to three sig figs and be sure to include units.

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C) From the non-participant's perspective, what are some of the benefits/costs that E&T framework fail to consider? (List at least 2)

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The group of vertebrae that make up the arched lower back portion of your spine are the ____ vertebrae. Lumbar Thoracic Sacral Cervical

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If we approximate ln(1.5) using Simpson's rule and using the same $f(x)$ we used in class for approximating ln(2), then we get ln(1.5) ? a. $\frac{816}{280}$ b. $\frac{241}{1080}$ c. $\frac{147}{180}$ d. $\frac{3}{4}$ e. $\frac{73}{180}$ f. None.

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Use the slider to change the value of k, and observe the effect on the graph. Equation 1, $y = 2^x$, is the parent exponential function. Equation 2, $y = a^x + k$, is a transformation of the parent function when a = 2 and k ? 0. Adjust the slider for k to observe what happens to the graph of the transformation.

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QRQ 6. In the first major part of cell respiration, through a series of reactions, one six-carbon sugar is converted to two three-carbon sugars - two molecules of pyruvate. The reactions also yield NADH and a net of ATP. QRQ 7. A nonprotein organic molecule that assists an enzyme with its catalytic function is called a coenzyme. QRQ 8. Complete the statement with answers selected from the following: ADP, ATP, FADH2, NADH, oxidized, reduced, respired. In redox reactions of cell respiration, the coenzyme FAD is reduced while NAD is oxidized. QRQ 9. When phosphate is added to a molecule, we say the molecule is phosphorylated. QRQ 10. The first major part of cell respiration, which starts with one six-carbon sugar, is called glycolysis.

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Find bases for the four fundamental subspaces of the matrix A as follows. N(A) = nullspace of A N(A$^T$) = nullspace of A$^T$ R(A) = column space of A R(A$^T$) = column space of A$^T$ Then show that N(A) = R(A$^T$)$^\perp$ and N(A$^T$) = R(A)$^\perp$. $\begin{bmatrix} 1 & 1 & 0 \\ 0 & 2 & -1 \\ 1 & 3 & -1 \end{bmatrix}$ N(A) = N(A$^T$) = R(A) = R(A$^T$) =

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X Connect X CH 4 Demo pt 1-YouTube x (102,735 unread) damien Callon.com/ext/map/index.html?_con-con&extemal browser=0&launchUrl=https%253A%252F%252Flms.mheducation.com%252Fmghmiddleware%252Fmheproducts Built Assignments i Saved Required information [The following information applies to the questions displayed below.] On April 1, 2015, Jiro Nozomi created a new travel agency, Adventure Travel. The following transactions occurred during the company's first month. April 1 Nozomi invested $35,000 cash and computer equipment worth $35,000 in the company. 2 The company rented furnished office space by paying $2,000 cash for the first month's (April) rent. 3 The company purchased $1,900 of office supplies for cash. 10 The company paid $2,100 cash for the premium on a 12-month insurance policy. Coverage begins on April 11. 14 The company paid $1,300 cash for two weeks' salaries earned by employees. 24 The company collected $9,500 cash on commissions from airlines on tickets obtained for customers. 28 The company paid $1,300 cash for two weeks' salaries earned by employees. 29 The company paid $550 cash for minor repairs to the company's computer. 30 The company paid $1,000 cash for this month's telephone bill. 30 Nozomi withdrew $2,000 cash from the company for personal use. Help Save & E Che

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