Section 3.4 Basis and Dimension: Problem 11
(1 point)
\begin{equation*}
Let \ A = \begin{bmatrix} 1 & -3 & 2 & 1 \\ -2 & 6 & -4 & -2 \end{bmatrix}
\end{equation*}
Find a basis of nullspace$(A)$.
Answer:
To enter a basis into WeBWork, place the entries of each vector inside of brackets, and enter a list of these vectors, separated by commas. For instance, if your basis is $\left\{ \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}, \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} \right\}$, then you would enter [1,2,3],[1,1,1] into the answer blank.
