2-5 Epsilon Delta: Problem 3
(1 point)
Let $f(x) = 6x + 1$. To prove that $\lim_{x \to 10} f(x) = 61$, we proceed as follows. Given any $\epsilon > 0$, we need to find a number $\delta > 0$ such that if $0 < |x - 10| < \delta$, then $|(6x + 1) - 61| < \epsilon$. What is the (largest) choice of $\delta$ that is certain to work? (Your answer will involve $\epsilon$. When entering your answer, type e in place of $\epsilon$.)
$\delta = $