Numerade

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Required Information Consider the given figure. Given: P=5.50kN and Q=11kN. A Pratt roof truss is loaded as shown. Determine the force in members FH,Fl, and Gl. The force in members FH is kN The force in members( F)/( i)s kN (Click to select) vv The force in members (G)/() is kN

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\[ \begin{aligned} p^{\prime \prime}\left(x_{2}\right) & =2 U\left[x_{1}, x_{2}, x_{3}\right] \\ & =2\left(\frac{U_{3}-U_{2}}{h_{2}}-\frac{U_{2}-U_{1}}{h_{1}}\right) /\left(h_{1}+h_{2}\right) \\ & =c_{1} U_{1}+c_{2} U_{2}+c_{3} U_{3} \end{aligned} \] where \[ c_{1}=\frac{2}{h_{1}\left(h_{1}+h_{2}\right)}, \quad c_{2}=-\frac{2}{h_{1} h_{2}}, \quad c_{3}=\frac{2}{h_{2}\left(h_{1}+h_{2}\right)} \] This would be our approximation to $ u^{\prime \prime}\left(x_{2}\right) $. The same result can be found by the method of undetermined coefficients. To compute the error in this approximation, we can expand $ u\left(x_{1}\right) $ and $ u\left(x_{3}\right) $ in Taylor series about $ x_{2} $ and find that \[ \begin{array}{l} c_{1} u\left(x_{1}\right)+c_{2} u\left(x_{2}\right)+c_{3} u\left(x_{3}\right)-u^{\prime \prime}\left(x_{2}\right) \\ \quad=\frac{1}{3}\left(h_{2}-h_{1}\right) u^{(3)}\left(x_{2}\right)+\frac{1}{12}\left(\frac{h_{1}^{3}+h_{2}^{3}}{h_{1}+h_{2}}\right) u^{(4)}\left(x_{2}\right)+\cdots \end{array} \] In general, if $ h_{1} \neq h_{2} $, the error is proportional to $ \max \left(h_{1}, h_{2}\right) $ and this approximation is "first order" accurate. In the special case $ h_{1}=h_{2} $ (equally spaced points), the approximation (1.14) reduces to the standard centered approximate $ D^{2} u\left(x_{2}\right) $ from (1.13) with the second order error shown there.

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Which sociological perspective would most likely suggest that sports help to maintain people's physical well-being? functionalist perspective conflict perspective interactionist perspective feminist perspective

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Express $ \cos X $ as a fraction in simplest terms.

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Evaluate $int_{0}^{10} (2x+1) dx$ and draw a picture of the area being found.

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Consider the following demand schedule for shoes: Price: $5 Quantity Demand: 385

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1. Looking at the graph above, if a monopolist lowers the price from $16 to $14, the quantity consumers are willing and able to buy changes from A) 10 to 4 B) 3 to 2 C) 2 to 3 D) 4 to 10 2. Looking at the above graph, total revenue at a price of $16 is A) 2 x $16 = $32 B) 2 x $14 = $28 C) 3 x $16 = $48 3. Looking at the above graph, at a price of $14, what is total revenue? A) 3 x $14 = $42 B) 2 x $14 = $28 C) 3 x $16 = $48 4. Looking at the graph above, when the monopolist lowers its price from $16 to $14, the marginal revenue is A) $10, which is below the price of the product. B) $10, which is above the price of the product. C) $14, which is equal to the new price of the product. Price $20 Revenue loss=$4 Revenue gain=$14 Marginal revenue $14$4$10 Cowen/Tabarrok, Modern Principles of Economics, 5e ©2021 Worth Publishers Demand 6 10 2 3 4 6 Marginal Quantity revenue 17 16 15 14 13 12 11 10 8 7 6 5 4 3 2 1

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Texts: Market Data Consider a segment of the fast food industry such as pizza (Domino's, Papa John's) or burgers (McDonald's, Wendy's), fried chicken, and so on. To ground your thinking, list the names of 5 companies from the segment you choose. Respond to the following: What type of market data can these companies collect? How might this data be used in marketing planning? Brand Equity Consider a product you are familiar with. Analyze its brand equity in the following areas: Brand awareness Brand loyalty Perceived quality Brand associations Brand assets Ethical and Legal Considerations in Social Media Marketing Find a current news article in which ethical or legal concerns have been raised regarding social media marketing.

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Find $V_o$ in the circuit in the figure using nodal analysis. 1 k$\Omega$ $\frac{V_o}{2}$ +- $V_o =$ 9 k$\Omega$ +- 12 V + 2 k$\Omega$ $V_o$ 0 -

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Problem 1: Write the answer in rectangular formats (a) \((50 \angle 60^\circ)(4 \angle 80^\circ) = \underline{\qquad} (b) \((0.8 \angle -10^\circ)(3 \angle 30^\circ)(-4 \angle 20^\circ) = \underline{\qquad} (c) \((5 + j8)(4 - j2) = \underline{\qquad} (d) \((48 \angle 20^\circ)(10 - j1) = \underline{\qquad} (e) \((0.9 - j0.5)(40 + j10) = \underline{\qquad} (f) \((4000 \angle 20^\circ)(2000 \angle -20^\circ)(1000 + j1000) = \underline{\qquad}

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lisa b.