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lisa ramirez

lisa r.

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Which of the following is a correctly drawn half reaction for an oxidation? Cu2+ + 2e- -> Cu Zn -> Zn2+ + e- Zn + Cu2+ -> Zn2+ + Cu Zn -> Zn2+ + 2e- Zn2+ + 2e- -> Zn

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Which of the following could be a bodily function affected by one of the hormones released by the posterior pituitary? maturation of the egg and sperm decrease in calcium levels increase in thyroid hormone level water retention

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What is the name of the process in which glucose is converted to pyruvate? none of the above Citric Acid Cycle Chemiosmosis Fermentation Glycolysis

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How did the terrorist attacks on September 11, 2001, alter George W. Bush's presidency? They allowed him to pass more of his domestic agenda. They undermined his authority as a strong wartime president. They provided him with the opportunity to focus on domestic affairs. They led to protracted wars in Afghanistan and Iraq.

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Question 4 A mutex lock O is exactly like a counting semaphore O can be used to protect the critical section's execution from being interleaved by other processes O is not guaranteed to be atomic O can be used to eliminate busy waiting

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QUESTION 1 What is the type of the staining used for this slide?

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In a test of the hypothesis Ho: M = 50 Ha: M > 50 a sample n= 100 observations possessed a mean of 49.4 and a standard deviation = 4.1. Answer the following questions: The p-value The form of these hypotheses is The test statistic = The decision based on the test statistic and the p-value is

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# Picking out the qualified pair options = options[which(options$impl_volatility != '' & XXXXXX),] # observations with nonmissing impl_volatility and non-zero open interest options = options[order(options$PERMNO, options$daystm, XXXXXX, XXXXXX),] # Sort the observations based on the following order: PERMNO, daystm, cstrike, and cp_flag a = as.data.frame(options %>% group_by(PERMNO, daystm, cstrike) %>% mutate(count = XXXXXX)) # Count the number of call and put. b = a[which( XXXXXX ),] # Keep the options whose number of call and put is 2. c = as.data.frame(b %>% group_by(PERMNO) %>% mutate(sums = sum(open_interest))) # Count the total number of open interest for each stock. # match the put option with the call option for within each call-put pair vol_put = c(c$impl_volatility[-1], 999) # delete the first observation in the impl_volatility vector and add the number 999 to the tail of the vector. open_put = c(c$open_interest[-1], 999) # delete the first observation in the open_interest vector and add the number 999 to the tail of the vector. # Try to understand why we do the two steps above. If you do not understand, send me an email. # A quick hint here is that, we are merging "vol_put" and "open_put" in the next step so that the call is matched with the corresponding put. d = cbind(c, vol_put, open_put) # combine the data set c with the two new vector we created, "vol_put" and "open_put". d = d[which( XXXXXX ),] # Keep only the call options d$vol_dif = d$impl_volatility - d$vol # calculate the impl_volatility difference between the call and the put option d$weights = (XXXXXX + XXXXXX) / XXXXXX # calculate the weight for each call-put pair e = as.data.frame(d %>% group_by(XXXXXX) %>% mutate(VS = sum(XXXXXX * XXXXXX))) # Calculate the measure VS for each stock f = cbind(XXXXXX, XXXXXX, XXXXXX) # Keep the stock (PERMNO), the next month return (RET), and the VS measure columns g = unique(f) # keep only the unique values for each stock g = g[order(XXXXXX),] # sort the data based on the VS measure. HINT: here you cannot use the g$VS notation since it is defined as a matrix. You need to specify the column number g = g[!is.na(g[,2]),] # delete the data whose second column (recall that this column is the RET column) contains missing values. short = mean(head(g[,2], floor(nrow(g)/10))) # keep the top 10 percent of observations and calculate the mean return among the stocks. long = mean(tail(g[,2], floor(nrow(g)/10))) # keep the bottom 10 percent of observations and calculate the mean return among the stocks. longshort = long - short # Calculate the return difference between the long and short portfolio short long longshort Library(dplyr) # Picking out the qualified pair options = options[which(options$impl_volatility != " & XXXXXX ),] # observations with nonmissing impl_volatility and non-zero open interest options = options[order(options$PERMN0, options$daystm, XXXXXX, XXXXXX),] # Sort the observations based on the following order: PERMNO, daystm, cstrike, and cp_flag a = as.data.frame(options %>% group_by(PERMNO, daystm, cstrike) %>% mutate(count = XXXXXX)) # Count the number of call and put. b = a[which( XXXxxX ),] # Keep the options whose number of call and put is 2. c = as.data.frarre(b X>X group_by(PERMNO) %>% mutate(sums = sum(open_interest))) # Count the total number of open interest for each stock. # match the put option with the call option for within each call-put pair vol_put = c(c$impl_volatility[-1], 999) # delete the first observation in the impl_volatility vector and add the number 999 to the tail of the vector. open_put = c(cSopen_interest[-1], 999) # delete the first observation in the open_interest vector and add the number 999 to the tail of the vector. # Try to understand why we do the two steps above, If you do not understand, send me an email. # A quick hint here is that, we are merging "vol_put" and "open_put" in the next step so that the call is matched with the corresponding put. d = cbind(c, vol_put, open_put) # combine the data set c with the two new vector we created, "vol_put and "open_put". d = d[which( xxxxxx,] #Keep only the call options d$vol_dif = d$impl_volatility - dSvol # calculate the impl_volatility difference between the call and the put option e = as.data.frame(d X>X group_by(XXXXXX) %>% mutate(VS = Sum(XXXXXX * XXXXXX))) # Calculate the measure VS for each stock f = cbind(xxXXXX, xXXXXX, xXXXXX) # Keep the stock (PERMNO), the next month return (RET), and the VS measure columns g = unique(f) # keep only the unique values for each stock g = g[order(XXXXxX),] # sort the data based on the VS measure. HINT: here you cannot use the g$VS notation since it is defined as a matrix. You need to specify the column number g = g[!is.na(g[,2]),] # delete the data whose second column (recall that this column is the RET column) contains missing values. short = fean(head(g[,2], floor(nrow(g)/10))) # keep the top 10 percent of observations and calculate the mean return among the stocks. long = mean(tail(g[,2], floor(nrow(g)/10))) # keep the bottom 10 percent of observations and calculate the mean return cmong the stocks. Longshort = Long - short # Calculate the return difference between the long and short portfolio short long longshort

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Write a definite integral that gives the length of the curve $x(t) = t + e^t$, $y(t) = 1 - e^t$ from $t = -2$ to $t = 3$. Do not evaluate your integral!

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K3:ek ba?lant? K2 dirsek Q K4: vana K5:ç?k?? Boru çap?: D Boru uzunlu?u: L K1: giri? P Dalg?ç pompa Elektrik EM motoru

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