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Maggie Pags

Maggie P.

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INSTANT ANSWER

Coordinate Systems conversion/Component Vectors 1. The polar coordinates of a point are \( r=5.50 \mathrm{~m} \) and \( \theta=240^{\circ} \). What are the Cartesian coordinates of this point? 2. Obtain expressions in component form for the position vectors having the following polar coordinates: (a) \( 12.8 \mathrm{~m}, 150^{\circ} \) (b) \( 3.30 \mathrm{~cm}, 60.0^{\circ} \) (c) \( 22.0 \) in., \( 215^{\circ} \) 3. Solve for the resultant of \( \vec{A}=2.5 \mathrm{~N}, 16.0^{\circ} \mathrm{N} \) of \( \mathrm{E} \), and \( \overrightarrow{\mathrm{B}}=10.0 \mathrm{~N}, 40^{\circ} \mathrm{E} \) of \( \mathrm{N} \) using component method. 4. Solve for the resultant of \( \vec{A}=3.0 \mathrm{~N}, 150 \circ, \vec{B}=2.0 \mathrm{~N}, 100^{\circ} \) and \( \overrightarrow{\mathrm{c}}=1.0 \mathrm{~N}, 50^{\circ} \) using component method. 5. Solve for the resultant of \( \vec{A}=35.0 \mathrm{~N}, 15.0 \circ, \overrightarrow{\mathrm{B}}=20.0 \mathrm{~N}, 45 \circ \mathrm{W} \) of \( \mathrm{N} \) and \( \overrightarrow{\mathrm{c}}=25.0 \) N, \( 30^{\circ} \mathrm{E} \) of \( \mathrm{N} \) using component method.

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Please give me a complete explanation

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INSTANT ANSWER

Part \( C \). Heat of Neutralization. Fill up the blank. Attach your computation for Heat and Enthalpy of neutralization. Molarity of \( \mathrm{HCl}= \) \( M \) Molarity of \( \mathrm{NaOH}= \) \( M \) Volume of \( \mathrm{HCl} \) used \( = \) \( \mathrm{mL} \) Volume of \( \mathrm{NaOH} \) used \( =\ldots \) Initial temperature of \( \mathrm{HCl}= \) \( { }^{\circ} \mathrm{C} \) Initial temperature of \( \mathrm{NaOH}= \) \( { }^{\circ} \mathrm{C} \) Final temperature of the mixture = \( { }^{\circ} \mathrm{C} \) Heat of Neutralization \( \left(-q_{r \times n}\right)= \) \( \mathrm{J} \) Enthalpy of neutralization \( \left(\Delta H_{n}\right)= \) \( \mathrm{J} / \mathrm{mol} \mathrm{H}_{2} \mathrm{O}= \) \( \mathrm{kJ} / \mathrm{mol} \mathrm{H}_{2} \mathrm{O} \) Answe with text and/or attachments.

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INSTANT ANSWER

Fill in the blanks: C. Heat of Neutralization (10 points) (1) Molarity of \( \mathrm{HCl}=1.0 \) \( \mathrm{M} \) (2) Molarity of \( \mathrm{NaOH}=1.0 \) \( \mathrm{M} \) (3) Volume of HCl used = \( \mathrm{mL} \) (4) Volume of \( \mathrm{NaOH} \) used \( =25 \) \( \mathrm{mL} \) (5) Initial temperature of \( \mathrm{HCl}= \) \( \begin{array}{ll}23.1 & { }^{\circ} \mathrm{C}\end{array} \) (6) Initial temperature of \( \mathrm{NaOH}= \) \( { }^{\circ} \mathrm{C} \) (7) Final temperature of the mixture (Experimental value) \( =29.8 \quad{ }^{\circ} \mathrm{C} \) (8) Heat of Neutralization \( \left(-q_{r x n}\right)= \) J (express your answer in two decimal digits) (9) Enthalpy of neutralization \( \left(\Delta H_{n}\right)= \) \( \mathrm{J} / \mathrm{mol} \mathrm{H}_{2} \mathrm{O} \) (express your answer in two decimal digits) (10) Enthalpy of neutralization \( \left(\Delta H_{n}\right)= \) \( \mathrm{kJ} / \mathrm{mol} \mathrm{H}_{2} \mathrm{O} \) (express your answer in two decimal digits)

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