A proton moves in the magnetic field $\vec{B}=0.14 \hat{i}$ T with a speed of $1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}$ in the directions shown in (Figure 1) and (Figure 2).
What is the magnetic force $\vec{F}$ on the proton in (Figure 1)?
Enter components of the force in piconewtons separated by commas.
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$F_{x}, F_{y}, F_{z}=0,-0.22,0 \mathrm{pN}$
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Term 2: Correct answer is shown. Your answer $-0.224 \mathrm{pN}$ was either rounded differently or used a different number of significant figures than required for this part.
MODEL: A magnetic field exerts a magnetic force on a moving charge.
SOLVE: The force on the charge is
$\vec{F}_{\text {on q }}=q \vec{v} \times \vec{B}=\left(1.60 \times 10^{-19} \mathrm{C}\right)\left(1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\right)(-\hat{k}) \times(0.14 \hat{i} \mathrm{~T})=-2.2 \times 10^{-15} \hat{j} \mathrm{~N}$
Part B
What is the magnetic force $\vec{F}$ on the proton in (Figure 2)?
Enter components of the force in piconewtons separated by commas.
View Available Hint(s)
$F_{x}, F_{y}, F_{z}=$ pN
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Figure
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z
$\vec{v}$
45°
y
x
$\vec{B}$
