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Q5 (6 points) Compute f^(')(x) if f(x)=tan^(-1)((x)/(7)). Q5 (6 points) Compute $f'(x)$ if $f(x) = \tan^{-1}(\frac{x}{7})$.

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3.13 Nonlinear data correlation Saccharomyces cerevisiae cells are homogenised to release recombinant hepatitis B surface antigen for vaccine production. During homogenisation, fractional protein release is predicted to follow the equation: where Sp is the fractional protein release, k is a constant dependent on the operating pressure of the homogeniser, and t is time. At a fixed pressure, the following data are obtained. Time (s) Fractional protein release (−) 20 0.25 30 0.31 60 0.62 90 0.75 120 0.79 150 0.88 (a) Is the predicted model a reasonable one for this system? (b) What is the value of k? (c) What time is required to release 50% of the protein? (d) What time is required to release 95% of the protein? How good is your answer?

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Problem 1: Discrete Let be $x[n] = [4\ 0\ 3\ 0\ 3\ 0\ 2\ 0\ 1]$ Draw $x[n]$, $x[n-5]$, $x[n+4]$, $x[2n]$, $2x[n]$, $x[n/2]$

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D. In the figure below, $ \overline{S U} $ and $ \overline{W U} $ are secant segments and $ \overline{X U} $ is a tangent segment. If $ \mathrm{WU}=14, \mathrm{ST}=12 $, and $ \mathrm{TU}=4 $, find: 1. VU 2. XU

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STATISTICS DATA ANALYSIS WITH CONFIDENCE INTERVALS PROF. A. ESTRADA PART I: WHEN CONFIDENCE INTERVALS GO BAD! I want to estimate the true average height for all women in the world. I collect 4 different samples of 15 women. Assume a parametric distribution is formed. The raw data is presented below. Sample 1 Sample 2 Sample 3 Sample 4 1 5.1 5.5 5.9 5.0 2 5.0 5.3 6.0 5.2 3 5.3 5.4 6.3 5.0 4 5.5 5.5 6.2 5.2 5 5.4 5.4 6.1 5.3 6 5.3 5.5 5.9 5.5 7 5.5 5.3 5.8 5.6 8 5.4 5.3 6.0 5.1 9 5.3 5.4 6.0 5.2 10 5.2 5.1 6.1 5.5 11 5.1 5.4 6.2 5.5 12 5.4 5.2 6.3 4.8 13 5.1 5.3 6.4 5.4 14 5.2 5.4 6.1 5.3 15 5.3 5.5 6.2 5.2 From the above raw data, SPSS constructed confidence intervals for each of the four samples at 99%. (Sample 1) 5'2" ≤ μ ≤ 5'5" (Sample 3) 6'0" ≤ μ ≤ 6'3" (Sample 2) 5'3" ≤ μ ≤ 5'5" (Sample 4) 5'1" ≤ μ ≤ 5'5" It is later discovered that μ = 5'4", which interval failed? Why do you think the confidence interval (Sample 3) was so far off? Look what happens when I combined all four samples of 15 different women into a single sample of 60 and construct a 99% confidence interval. One-Sample Test Test Value = 0 99% Confidence Interval of the Difference Sample_1 t df Sig. (2-tailed) Mean Difference Lower Upper 109.230 59 .000 5.4983 5.364 5.632 5'4" ≤ μ ≤ 5'8" Based on the confidence interval constructed above, what statements can you make? BIG PICTURE SUMMARY: What can be done to increase the overall accuracy of a statistical test?

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If the auditor determines controls are effective, what conclusion will they likely make? O controls will not be tested O control risk is high O inherent risk is low O controls will be relied on

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Question 3 In the context of the classic theories of language acquisition, the nativist approach A states that speech development is independent of having someone to talk with in a person's native language. B accurately explains why children differ in their linguistic skills and fluency. C suggests that almost all children master their native language in the same age-related sequence without formal teaching. D provides sufficient reasoning as to why some children acquire language more rapidly and efficiently than others.

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art of the New Deal this act provided federal loans to save private banks

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One of the simplest quintic polynomials we can actually solve is z5+1=0 This can be rewritten as

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Channel protein The diagram above shows a section of a cell membrane that includes a channel protein. Which type of transport would the channel protein be needed for molecules to pass through the membrane?

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mark r.