Use a one-sample T test, based on the data below, to test the null hypothesis $H_0: \mu = 100.63$ against the alternative hypothesis $H_1: \mu \neq 100.63$. The sample has a mean of $\bar{x} = 101.09$ and a standard deviation of $s = 0.4887$.
100.68, 101.23, 100.82, 101.15, 100.96, 100.70, 102.09
Calculate the standard error (SE) and the T statistic for this test. Give the standard error to four decimal places and $t$ to three decimal places.
SE =
t-statistic =