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matthew franklin

matthew f.

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Runaway slaves were disorganized, confused, and didn’t know how to build their own socieƟes. They therefore copied European society as best as they could. A perfect example of this is Palmares in colonial Brazil. As one primary source states: “They imitate everything found in a republic.” The source elaborates that Palmares had its own fake “king” and a supposedly ChrisƟan church that performed marriages, but these were not true or real. Unsurprisingly, living in such a false society, social problems were everywhere. As the source states: “Lust is the rule for selecƟon of mates, and each has the women he desires.” With men so out of control, the society must have been hell for women. But not only for women; rather, Palmares “wreaked havoc on life, honor, and possessions.” The whole thing was senseless. As one eyewitness observer remarked, “With so much imaginaƟon, they felt more secure where they could be more at risk.” In other words, they would have been beƩer off back on the plantaƟon where they belonged.

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The Global Financial Stability Report is a semiannual report published by the International Capital Markets division of the International Monetary Fund. How do issues from five years ago compare with financial issues identified in the current report

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QUESTION 32 Generally, it is impossible for measures to be neither reliable nor valid. both reliable and valid. valid but not reliable. reliable but not valid.

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(d) The 6 kg cylindrical collar is released from rest in the position shown and drops onto the spring as depicted in Fig. Q1d. What is the velocity of the cylinder when the spring has been compressed by 50 mm.? [4 M] $T_1 + V_1 = T_2 + V_2$ 0 + 0 $= \frac{1}{2} \times 6 \times v^2 = 6 \times 9.81 \times 0.550$ $+ \frac{1}{2} \times 12000 \times 0.050$ $v = 2.4064 \text{ m/s}$

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Question number 16. Mr. Sosa, Mrs. Perepelitsa, and Mr. Dougmay wanted to compute the area under the curve $f(x) = x^{-6} + 2x - 6x^2 + cos(x)$ over the interval $[2, 10]$. To do this, each one used a different anti-derivative. Mrs. Perepelitsa used the antiderivative $F(x) = \frac{1}{5x^5} + x^2 - 2x^3 + sin(x)$. Mr. Sosa used the antiderivative $F(x) = -\frac{x^{-5}}{5} + x^2 - 2x^3 + sin(x) + 2020$. Mr. Dougmay used the antiderivative $F(x) = -6x^{-7} + x^2 - 2x^3 + sin(x)$. Who, if anyone, completed this problem correctly? Only Mr. Sosa and Mrs. Perepelitsa Only Mr. Sosa Only Mrs. Perepelitsa Only Mr. Dougmay All three are correct None of them.

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Need to know the mechanism steps to get to the product from the reactants

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Two Systems of Charges Points: 2 Consider two separate systems, each with four charges of magnitude $q$ arranged in a square of length $L$ as shown above. Points $a$ and $c$ are in the center of their squares while points $b$ and $d$ are half way between the lower two charges. Select True or False for the following statements. The electric field at $a$ is zero. The electric potential at $d$ is zero. The electric field at $c$ is zero. The electric potential at $a$ is zero. The electric field at $b$ is zero. The electric potential at $b$ is zero. The electric potential at $c$ is zero. The electric field at $d$ is zero. Using the diagram above, find the magnitude of the electric field at point $d$. DATA: $q = 1.150 \mu C$, $L = 0.40 \ m$

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A 70-year-old man is brought to the ER following an ischemic stroke. MRI shows an infarcted area in the brain on the right side. The neurological examination reveals dysphagia, dysphonia, ataxia, and a left hemiparesis. This combination of deficits would most likely indicate a vascular occlusion of which of the following arteries? • A. Vertebrobasilar artery system • B. ACA • C. Lenticulostriate • D. MCA

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Question 2. Two steel plates of uniform cross section 10 mm x 80 mm are welded together as shown. Knowing that centric 100 KN forces are applied to the welded plates and that the weld make an angle of $\beta = 25^\circ$, determine: (a) the in-plane shearing stress parallel to the weld, (b) the normal stress perpendicular to the weld.

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rt 1 - Wave Physics 1.500 1.000 0.500 0.000 -0.500 -1.000 -1.500 0 50 100 150 200 250 300 350 400 450 500 550 600 650 700 750 For the time-series signal shown above: Time in milliseconds(ms)

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