2. Assume that you know that dG is a perfect differential, that \( \mathrm{dG}=\mathrm{pdV}-\mathrm{TdS} \) and that \( (\mathrm{dp} / \mathrm{dT})_{\mathrm{V}}=(\mathrm{dS} / \mathrm{dV})_{\mathrm{T}} \), or as you have learned in MATH \( 2 \mathrm{~A},(\delta \mathrm{p} / \delta \mathrm{T})_{\mathrm{v}}=(\delta \mathrm{S} / \delta \mathrm{V})_{\mathrm{T}} \). Now consider the vapor pressure diagram for water, where the equilibrium line between the solid phase and the liquid phase has a negative slope. What does this imply when water freezes or melts at any equilibrium temperature? dG is the change in the Gibb's Free Energy, and represents the net energy change in a process. If \( \mathrm{dG}=0 \), the process is in a state of equilibrium.
