Suppose events A and B are independent with $P(A \cup B) = 0.8988$, $P(A) = 0.78$, and $P(B) = 0.54$. The probability of $A \cap B^c$ is computed as (Note: If none of these are correct, write "x" as your solution.)
a. 0.3591
b. 0.0994
c. 0.9268
d. 0.3588
e. 1.32